First, given graph is very inaccurate. I suppose that you made net with pen.
a) The slope is the angle ( tan∡) between your graph and x axis.
The slope represent the level of the earnings growth.
b) According to the given graph y-intercept= 30$
Y-intercept represent starting amount of money.
c) If we accept that y=70 is connected with x=2 and y=30 with x=0
The slope is S= (70-30)/2= 40/2=20
Linear equation for this function is
y= 20x+30
d) When we replace y=300$ in the equation we get
20x+30=300 => 20x=300-30 => 20x=270 => x=270/20=13.5h
x=13.5h
Good luck!!!
y=6x-3
put a point on (0,-3) this is your y intercept
go up 6 and over 1 this should land you at (1,0) do this again and your at (2,6)
go back to the y intercept now go down 6 and over 1, this should land you (-1,-6)
continue to do this until you graph is filled
X= -46 and y = -40 I worked it out I might be wrong
Answer:
Midpoint of AB = (0 + 2a / 2 , 0 + 0 / 2) = (2a / 2 , 0 / 2) = (a,0)
x coordinate of point c = a
N = (0 + a / 2 , 0 + b / 2) = (a / 2 , b / 2)
M = ( 2a + a / 2 , 0 + b / 2) = (3a / 2 , b / 2)
MA = √(3a / 2 - 0)² + b / 2 - 0)²
= √(3a / 2 )² + (b / 2) = 9a² / 4 + b² / 4
NB = √(a / 2 - 2a)² + (b / 2 - 0 )²
= √( a / 2 - 4a / 2)² + (b / 2 - 0)²
= √(-3a / 2)² + (b / 2)² = √9a² / 4 + b² / 4
Step-by-step explanation:
I tried my best hope its correct :0
