Answer:
m<SQP=124°
Step-by-step explanation:
Hi there!
We're given ΔQRS, the measure of <R (90°), and the measure of <S (34°)
we need to find m<SQP (given as x+72°)
exterior angle theorem is a theorem that states that an exterior angle (an angle on the OUTSIDE of a shape) is equal to the sum of the two remote interior angles (the angle OUTSIDE of a shape will be equal to the sum of 2 angles that are OPPOSITE to that angle).
that means that m<SQP=m<R+m<S (Exterior angle theorem)
substitute the known values into the equation
x+72°=90°+34° (substitution)
combine like terms on both sides
x+72°=124° (algebra)
subtract 72 from both sides
x=52° (algebra)
however, that's just the value of x. Because m<SQP is x+72°, add 52 and 72 together to get the value of m<SQP
m<SQP=x+72°=52°+72°=124° (substitution, algebra)
Hope this helps!
Answer:
1)
2) 
Step-by-step explanation:
Please ignore the squiggle in the middle of the page.
Please mark brainliest when you’re able :)
Answer:
42
Step-by-step explanation:
5 * 4 + (6 / [ 2 + 1 ] ) *11
5 * 4 +2 * 11
20 +2 * 11
20+ 22
42
I believe the answer is B for this question
The solution to the equation includes both the positive and negative portions of the solution. x = 12, -12