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AlekseyPX
3 years ago
10

Your answer should be a polynomial in standard form. (-1+2p)(3-4p)=(−1+2p)(3−4p)

Mathematics
1 answer:
saul85 [17]3 years ago
5 0

\\ \rm\Rrightarrow (-1+2p)(3-4p)=(-1+2p)(3-4p)

\\ \rm\Rrightarrow \dfrac{(-1+2p)(3-4p)}{(-1+2p)(3-4p)}=1

\\ \rm\Rrightarrow 1=1

\\ \rm\Rrightarrow 1-1

\\ \rm\Rrightarrow 0

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Pls help need ASAP been stuck on these problems for a few now
kodGreya [7K]

Answer:

C. AC/BC = DF/EF

Step-by-step explanation:

Hi en that ∆ABC ~ ∆DEF, the corresponding sides of ∆ABC and ∆DEF would be proportional to each other.

AB corresponds to DE

AC corresponds to DF

BC corresponds to EF

Therefore,

hypotenuse over one of the leg of ∆ABC = hypotenuse over one of the corresponding legs of ∆DEF, which is:

AC/BC = DF/EF

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A classroom fish tank contains x goldfish the tank contains four times as many cups as goldfish enter an equation that represent
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2 years ago
A simple random sample of size n = 49 is obtained from a population with u = 89 and o = 21.
Furkat [3]

Answer:

a) B. The distribution is approximately normal.

b) 0.0322 = 3.22%

c) 0.0202 = 2.02%

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean  and standard deviation , the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean and standard deviation:

\mu = 89, \sigma = 21

Sample of 49:

This means that n = 49, s = \frac{21}{\sqrt{49}} = 3

(a) Describe the sampling distribution of x.

By the Central Limit Theorem, approximately normal, and the correct answer is given by option B.

(b) What is P (x > 94.55) ?

This is 1 subtracted by the p-value of Z when X = 94.55, so:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{94.55 - 89}{3}

Z = 1.85

Z = 1.85 has a p-value of 0.9678.

1 - 0.9678 = 0.0322

So 0.0322 = 3.22%

Question c:

This is the p-value of Z when X = 82.85. So

Z = \frac{X - \mu}{s}

Z = \frac{82.85 - 89}{3}

Z = -2.05

Z = -2.05 has a p-value of 0.0202.

So

0.0202 = 2.02%

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