Question

Your answer should be a polynomial in standard form. (-1+2p)(3-4p)=(−1+2p)(3−4p)

Answer 1

$\\ \rm\Rrightarrow (-1+2p)(3-4p)=(-1+2p)(3-4p)$

$\\ \rm\Rrightarrow \dfrac{(-1+2p)(3-4p)}{(-1+2p)(3-4p)}=1$

$\\ \rm\Rrightarrow 1=1$

$\\ \rm\Rrightarrow 1-1$

$\\ \rm\Rrightarrow 0$