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3 years ago

Your answer should be a polynomial in standard form. (-1+2p)(3-4p)=(−1+2p)(3−4p)

Mathematics

1 answer:

saul85 [17]3 years ago

5 0

$\\ \rm\Rrightarrow (-1+2p)(3-4p)=(-1+2p)(3-4p)$

$\\ \rm\Rrightarrow \dfrac{(-1+2p)(3-4p)}{(-1+2p)(3-4p)}=1$

$\\ \rm\Rrightarrow 1=1$

$\\ \rm\Rrightarrow 1-1$

$\\ \rm\Rrightarrow 0$

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Answer:

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Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

$H_0: \mu=2.4\\\\H_a:\mu> 2.4$

The significance level is 0.05.

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The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58$

The degrees of freedom for this sample size are:

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This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>2.5801)=0.0066$

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

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