I have 17 ones. I am between 30 and 40. What number am I?
2 answers:
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Kayla buys two pairs of jeans for j dollars each and one shirt for 15 dollars. The cost of one pair of jeans is $22.5 (twenty-two dollars and fifty cents)
From the given information
- Let the cost of two pairs of jeans be 2j
- The cost of 1 shirt = 15
- Total amount to spent = $60
∴
The equation is said to be expressed as:
- 2j + 15 - 60 = 0
Collect like terms
- 2j = 60 - 15
- 2j = 45
Divide both sides by 2
- j = 22.5
Therefore, we can conclude that the cost of one pair of jeans is $22.5 (twenty-two dollars and fifty cents).
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We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d
we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor
p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)
therefor
p=d(x+4) and
x^2-5x+6=d(x-2)
we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub
p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d
we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor
p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)
therefor
p=d(x+4) and
x^2-5x+6=d(x-2)
we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub
p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)