All categories

2 years ago

1. Write a ratio and a percent for the shaded area. (1 point)

Mathematics

1 answer:

Kipish [7]2 years ago

8 0

Answer:

3/10, 30%

Step-by-step explanation:

the shaded region is 9/30 which is equivilent to 3/10 and 3/10is 30 percent.

hope this helps!

You might be interested in

TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN

stich3 [128]

Answer:

A. It would be needed 20 packets to transmit 30,000 bytes of information and B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.

Step-by-step explanation:

1. Let's review the information provided to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

It would be needed 20 packets to transmit 30,000 bytes of information

B. How much information could be transmitted in 30,000 packets?

B = 30,000 * 1,500

B = 45'000,000

45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.

Note: Same answer provided to question 14037480, answered by me.

7 0

2 years ago

Is 4/5 greater or less than 45/100 how do you know

rusak2 [61]

Answer:

4/5 is grater than 45/100

Step-by-step explanation:

Why?

because in percentage you make the bottom # a 100 one of them already has that and when it has 100 on the bottom it tells you that the top # is the percentage so 45/100 is 45%

now to make 4/5 a percentage what times 5 = 100?

20 does

so you times the top and bottom by 20

4*20= 80

now your fraction is 80/100 (top # tells you the %)

it's 80%

80% is grater than 45%

5 0

2 years ago

Read 2 more answers

80 % of _ games is 32 games

andrew-mc [135]

80% × x = 32
.80x = 32
x = 32/.8
x = 40

7 0

2 years ago

Read 2 more answers

From first principles, find the indicated derivatives

LenaWriter [7]

By definition of the derivative,

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{(s + h)^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{s^3+3s^2h+3sh^2+h^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\frac{3s^2h+3sh^2+h^3}2}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 \frac{3s^2h+3sh^2+h^3}{h}$

$\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 (3s^2+3sh+h^2)$

$\displaystyle\frac{dr}{ds} = \frac{3s^2}2$

6 0

2 years ago

What is the function rule for the line?

11Alexandr11 [23.1K]

So with these equations we need to find the y-intercept and the slope because:

y = mx+b

y = f(×)

b = y-intercept

m = slope (slope = rise/run, rise over run)

rise is y-axis
run is x-axis

The y-intercept is (0,-2)
So now we know that one of the answers must have -2 in it

b = -2

m= rise/run = -2/3

The answer is:

$f(x) = - \frac{2 }{3 } x - 2$

5 0

2 years ago

Read 2 more answers