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noname [10]
3 years ago
7

Dean Halverson recently read that full-time college students study 20 hours each week. She decides to do a study at her universi

ty to see if there is evidence that students study an average of less than 20 hours each week. A random sample of 35 students were asked to keep a diary of their activities over a period of several weeks. It was found that he average number of hours that the 35 students studied each week was 18.5 hours. The sample standard deviation of 4.3 hours.
Find the p-value.
PS: If you know how to do this in excel, please explain how to do so but if you don't I would still greatly appreciate the answer you provide.
Mathematics
1 answer:
romanna [79]3 years ago
4 0

Answer: The p-value is 0.154.

Step-by-step explanation:

Since we have given that

We claim that

Null hypothesis :

H_0:\mu=20

Alternate hypothesis :

H_1:\mu

Population mean = 20 hours

Sample mean = 18.5 hours

Sample standard deviation = 4.3 hours

Sample size n = 35

So, test statistic would be

z=\dfrac{\bar{X}-\mu}{\dfrac{\sigma}{\sqrt{n}}}\\\\z=\dfrac{18.5-20}{\dfrac{4.3}{\sqrt{35}}}\\\\z=\dfrac{-1.5}{0.726}\\\\z=-2.066

So, the  p value would be 0.154.

Hence, the p-value is 0.154.

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Ms. Mor ris has 35 tests to grade this weekend. Mrs. Cook has 80% more tests than that to grade this weekend. How many tests doe
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Answer:

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Step-by-step explanation:

In order to find the answer, first you have to calculate 80% of the number of tests Ms. Morris has:

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Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

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