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3 years ago

Which table represents a linear function?

Mathematics

2 answers:

Andrew [12]3 years ago

8 0

Answer:

The first table is the only table representing a linear function.

Step-by-step explanation:

" You can tell if a table is linear by looking at how X and Y change. If, as X increases by 1, Y increases by a constant rate, then a table is linear. You can find the constant rate by finding the first difference. This table is linear."

P.S.

( thanks to G00GLE for the anwers, hat's off to the internet :^)

svet-max [94.6K]3 years ago

8 0

Option C

Here function is given by

$\\ \tt\bull\leadsto f(x)=x+6$

Linear function means it exists in one straight line .
If you plot the points they will exist in one line.

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A circle has the equation

Firlakuza [10]

Answer:

choice G. (-5, 2)

Step-by-step explanation:

(x + 5)^2 + (y - 2)^2 = 9

(x + 5)^2 + (y - 2)^2 = 3^2

center( -5, 2)

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3 years ago

Prove: △VWZ ≅ △YWZ

chubhunter [2.5K]

Answer:

Step-by-step explanation:

Statements Reasons

----------------------------------------------------------------

1. ∠V ≅ ∠Y Given

2. WZ bisects ∠VWY Given

3. ∠VWZ ≅ ∠YWZ Definition of Angle Bisector (2)

4. WZ ≅ WZ Reflexive Property

5. ΔVWZ ≅ ΔYWZ AAS Theorem (1,3,4)

**In case you didn't know the definitions**

Angle Bisector - A line, segment or ray that divides an angle into two congruent angles

Reflexive Property - X = X

AAS Postulate - If two angles and a non-included side of one triangle are congruent to the corresponding parts of another triangle, then the triangle's are congruent

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3 years ago

Which two values of x are roots of the polynomial below? x2-11x + 15

Alex787 [66]

The two values of roots of the polynomial $x^{2}-11 x+15$ are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

Solution:

Given, polynomial expression is $x^{2}-11 x+15$

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Given that $x^{2}-11 x+15$

Here a = 1, b = -11 and c = 15

On substituting the values we get,

$x=\frac{-(-11) \pm \sqrt{(-11)^{2}-4 \times 1 \times 15}}{2 \times 1}$

$\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}$

Hence, the roots of given polynomial are $\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}$

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3 years ago

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sasho [114]

Answer:

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Step-by-step explanation:

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4 years ago

Use the written method to solve: 1,365+1,289 . Please i need a quick help with this

julia-pushkina [17]

Step-by-step explanation:

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3 years ago

Which table represents a linear function?​

Which table represents a linear function?