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4 years ago

What is the fourth term of this sequence? a1 = 4, an = 5a n-1

Mathematics

1 answer:

pychu [463]4 years ago

7 0

Answer:

yes u no

Step-by-step explanation:

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A student found the slope of a line that passes through the points (3, 15) and (5, 9) to be . What mistake did he make?

Olenka [21]

I hope this helps you

slope=y2-y1/x2-x1

slope=9-15/5-3

slope= -6/2

slope = -3

4 0

3 years ago

Read 2 more answers

How do I find the slope of the line?

solniwko [45]

Answer:

where the dots are

Step-by-step explanation:

4 0

2 years ago

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Draw a rectangular fraction model to explain your thinking. Then, write a multiplication sentence. A. 2 3 of = 3 5

myrzilka [38]

Answer:

$\frac{2}{3}\ of\ \frac{3}{5} = \frac{2}{5}$

Step-by-step explanation:

Given

$\frac{2}{3}\ of\ \frac{3}{5}$

Solving (a): Multiplication sentence

$\frac{2}{3}\ of\ \frac{3}{5}$

Rewrite of as *

$\frac{2}{3}\ of\ \frac{3}{5} = \frac{2}{3}\ *\ \frac{3}{5}$

Solve

$\frac{2}{3}\ of\ \frac{3}{5} = \frac{2}{5}$

Hence, the multiplication sentence is:

$\frac{2}{3}\ of\ \frac{3}{5} = \frac{2}{5}$

Solving (b): Rectangular fraction model

In (a) above, the result is 2/5

The fraction model will be represented as thus:

Draw a rectangle
Partition in to 5 equal parts (5 represents the denominator)
Shade 2 of the 5 partitions (2 represents the numerator)

<em>See attachment for model</em>

5 0

3 years ago

It’s raining outside, and after 1 hour of rain, the water level in Jake’s pond is 2 meters. After 3 hours, the water level is 2.

GREYUIT [131]

Th state of change is 0.4 meters per hour

5 0

3 years ago

Suppose that demand in period 1 was 7 units and the demand in period 2 was 9 units. Assume that the forecast for period 1 was fo

Zepler [3.9K]

Answer:

Step-by-step explanation:

Forecast for period 1 is 5

Demand For Period 1 is 7

Demand for Period 2 is 9

Forecast can be given by

$F_{t+1}=F_t+\alpha (D_t-F_t)$

where

$F_{t+1}=Future Forecast$

$F_t=Present\ Period\ Forecast$

$D_t=Present\ Period\ Demand$

$\alpha =smoothing\ constant$

$F_{t+1}=5+0.2(7-5)$

$F_{t+1}=5.4$

Forecast for Period 3

$F_{t+2}=F_{t+1}+\alpha (D_{t+1}-F_{t+1})$

$F_{t+2}=5.4+0.2\cdot (9-5.4)$

$F_{t+2}=6.12$

8 0

3 years ago