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cupoosta [38]
3 years ago
8

Which sequence could be partially defined by the recursive f (n + 1) = f(n) + 2.5 for n > 1?

Mathematics
1 answer:
kow [346]3 years ago
4 0

Answer:

Step-by-step explanation:

f(n + 1) = f(n) + 2.5

f(1) = -10

f(2) = f(1) + 2.5 = -10 + 2.5 = -7.5

f(3) = f(2) + 2.5 = -7.5 + 2.5 = -5

f(4) = f(3) + 2.5 = -5 + 2.5 = -2.5

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Find the first 4 terms of the geometric sequence a1=40 and r=0.5
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For the answer to the question above, 
a1 = 40 
<span>a2 = 20 </span>
<span>a3 = 10 </span>
<span>.. </span>
<span>aN = (1/2^N-1) a1 { in general aN= (r^N-1) A1 </span>

<span>a5 = (1/2^4) 40 = 40/16 = 2.5
</span>
So the answer to your question is 2.5
I hope my answer helped you. Feel free to ask more questions. Have a nice day!
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gavmur [86]
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0            1
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Step-by-step explanation:

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