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3 years ago

15

A construction worker needs to pour a rectangular slab 25 ft long. 15 ft wide, and 4 in thick. How many cubic yards of concrete

does the worker need? (Assume that the construction worker carnot buy a fraction of a cubic yard of concrete)

1 answer:

arsen [322]3 years ago

3 0

Answer:

<em><u>hope </u></em><em><u>this </u></em><em><u>answer </u></em><em><u>helps </u></em><em><u>you </u></em><em><u>dear.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>!</u></em><em><u> </u></em>

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Danielle sells beauty supplies and earns a base salary of $450 per week plus a 9% commission on sales. During one particular wee

Anna007 [38]

Answer:

Should be 530.55 total that week

And 80.55 in commissions

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3 years ago

Which composition of transformations maps figure RSTUV to figure R"S"T"U"V"?

Sergeu [11.5K]

Answer:

option: B is correct

A reflection across line n followed by a 270° rotation about point P.

Step-by-step explanation:

Clearly from the figure we could see that the graph is first reflected across the given line n such that we obtain the figure R'S'T'V'U' and then it is rotated 270° across the point P so that we obtain the figure R"S"T"U"V".

Hence, option B is correct.

( A reflection across line n followed by a 270° rotation about point P )

5 0

3 years ago

Read 2 more answers

Please helppppppp!!!!!!!!!!!!!!!!!!!!!!!!!!!

Olin [163]

So here, ABCD is being inscribed in a circle, so ABCD is a cyclic quadrilateral (as inscribed in a circle) also, there exists a property of cyclic quadrilateral, i.e, the sum of opposite angles of a cyclic quadrilateral is 180°, so we can just write the following equation using this :

${:\implies \quad \sf y^{\circ}+83^{\circ}=180^{\circ}}$

${:\implies \quad \sf y^{\circ}=180^{\circ}-83^{\circ}}$

${:\implies \quad \sf y^{\circ}=97^{\circ}}$

${:\implies \quad \boxed{\bf{y=97}}}$

6 0

2 years ago

Translate and solve: 3884.4 is what percent of 46.8?

lisov135 [29]

Answer:

3884.4 is what percent of 46.8 is 8300

6 0

3 years ago

Internet Pricing An Internet Service Provider (ISP) offers its customers three options:

Mama L [17]

Answer:

(b)$29.62

(c)$5.73

Step-by-step explanation:

Basic: Standard internet for everyday needs, at $24.95 per month.

Premium: Fast internet speeds for streaming video and downloading music, at $30.95 per month.

Ultra: Super-fast internet speeds for online gaming at $40.95 per month.

Let the number of customers on Ultra=x; therefore:

Number of Premium customers =2x

Number of Basic customers =3x

Total=x+2x+3x=6x

$P(Ultra)=\dfrac{x}{6x}=\dfrac{1}{6} \\P(Premium)=\dfrac{2x}{6x}=\dfrac{1}{3}\\P(Basic)=\dfrac{3x}{6x}=\dfrac{1}{2}$

(a)X=Monthly fee paid by a randomly selected customer.

Therefore, the probability distribution of X is given as:

$\left|\begin{array}{c|c}X&P(X)\\---&---\\\$24.95&3/6\\\$30.95&2/6\\\$40.95&1/6\end{array}\right|$

(b)Average Monthly Revenue per customer

Mean,

$\mu=(\$24.95 \times 3/6)+(\$30.95 \times 2/6)+(\$40.95 \times 1/6)\\=\$29.62$

(c)Standard Deviation

$\left|\begin{array}{c|c|c|c|c}x&P(x)&x-\mu &(x-\mu)^2&(x-\mu)^2P(x)\\-----&-----&----&----&-----\\\$24.95&3/6&-4.67&21.8089&10.9045\\\$30.95&2/6&1.33&1.7689&0.5896\\\$40.95&1/6&11.33&128.3689&21.3948\\-----&-----&----&----&-----\\&&&&32.8889\end{array}\right|$

$\text{Standard Deviation}=\sqrt{(x-\mu)^2P(x)}\\=\sqrt{32.8889} \\ \sigma=\$5.73$

4 0

3 years ago