How to draw model for 3 ×40

True or False 4x + 2y - x = 3x + 2y

Zigmanuir [339]

Answer:

False

Step-by-step explanation:

3 0

3 years ago

A bag contains 28 colored marbles. There are 5 blue marbles, 9 red marbles, 11 yellow

Savatey [412]

Answer:

9:11

Step-by-step explanation:

8 0

3 years ago

which equation represents an exponential function that passes through the point (2, 80)? f(x) = 4(x)5 f(x) = 5(x)4 f(x) = 4(5)x

pav-90 [236]

we know that

if the exponential function passes through the given point, then the point must satisfy the equation of the exponential function

we proceed to verify each case if the point $(2,80)$ satisfied the exponential function

case A $f(x)=4(x^{5})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

so

$f(2)=4(2^{5})=128$

$128\neq 80$

therefore

the exponential function $f(x)=4(x^{5})$ not passes through the point $(2,80)$

case B $f(x)=5(x^{4})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

so

$f(2)=5(2^{4})=80$

$80=80$

therefore

the exponential function $f(x)=5(x^{4})$ passes through the point $(2,80)$

case C $f(x)=4(5^{x})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

so

$f(2)=4(5^{2})=100$

$100\neq 80$

therefore

the exponential function $f(x)=4(5^{x})$ not passes through the point $(2,80)$

case D $f(x)=5(4^{x})$

For $x=2$ calculate the value of y in the equation and then compare with the y-coordinate of the point

so

$f(2)=5(4^{2})=80$

$80=80$

therefore

the exponential function $f(x)=5(4^{x})$ passes through the point $(2,80)$

therefore

the answer is

$f(x)=5(x^{4})$

$f(x)=5(4^{x})$

7 0

3 years ago

A fruit company delivers its fruit in two types of boxes: large and small. A delivery of 3 large boxes and 5 small boxes has a t

Kaylis [27]

Answer:

Step-by-step explanation:

We need a system of equations here. The first equation is that 3L boxes + 5s boxes (L = large and s = small) = 88 kg so

3L + 5s = 88

12L + 2s = 235 according to the other information given.

Solve the first equation for either L or s. I'll solve for L, just because:

3L = 88 - 5s and

L = $\frac{88}{3}-\frac{5}{3}s$ and sub that into the second equation for L:

$12(\frac{88}{3}-\frac{5}{3}s)+2s=235$ and if you distribute the 12 into the parenthesis you'll simplify it down a bit to

352 - 20s + 2s = 235 and combine like terms:

-18s= -117 so

s = 6.5 kg and plug that in to solve for L:

L = $\frac{88}{3}-\frac{5}{3}(6.5)$ and

L = 18.5 kg

3 0

3 years ago

Suppose 240 nursing students took a certification test that is worth 140 points. The five-number summary for the scores is shown

Rus_ich [418]

180 is correct welcomes

4 0

4 years ago

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