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Fantom [35]
3 years ago
9

Jose is selling peanuts at the carnival. The original bag he purchased weighs 6 3/4 lbs. If the bags he plans on selling will we

igh 1/2 lb each, what is the maximum number of full 1/2 lb bags that he can sell?
Please provide an answer and explain.
Mathematics
1 answer:
Aleks04 [339]3 years ago
5 0

Answer:

13 bags

Step-by-step explanation:

1: If he has 6 3/4 lbs to start with, this is 6.75 lbs, as 3/4 = 0.75.

2: He wants the new bags to be 1/2 lb, which is 0.5 lbs.

3: If we divide 6.75 by 0.5, we get the exact number of bags he could have - 13.5.

4: However, the bags must be full, so we have to disregard that extra 0.5 bags, and say he can completely fill 13 bags.

Hope this helps! Let me know if you have any questions :)

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Read 2 more answers
Jessie estimates the weight of her cat to be 10 pounds. The actual weight of the cat is 13.75 pounds. find the percent error.
romanna [79]

Answer:

\large \boxed{27 \, \%} }

Step-by-step explanation:

\begin{array}{rcl}\text{Percent error}&= &\dfrac{\lvert \text{Measured - Actual}\lvert}{ \text{Actual}} \times100 \,\%\\\\& = & \dfrac{\lvert 10 - 13.75\lvert}{13.75} \times 100 \, \% \\\\& = & \dfrac{\lvert -3.75\lvert}{13.75} \times 100 \, \%\\ \\& = & \dfrac{3.75}{13.75} \times 100 \,\%\\\\& = & 0.27 \times 100 \, \%\\& = & \mathbf{27 \, \%}\\\end{array}\\\text{The percent error is $\large \boxed{\mathbf{27 \, \%} }$}

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