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2 years ago

HELP PLS!! a,b,c,d??

Mathematics

2 answers:

Gnoma [55]2 years ago

6 0

Answer:

the correct answer is A because 3 is the rise over run or the slope while 2 is the base or starting value

Sphinxa [80]2 years ago

4 0

Answer:

BRAINLY PLEASE

Step-by-step explanation:

y=-3x+2

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Can u please help me??

frez [133]

Answer:

Given GP:

tₙ = (1/3)ⁿ⁻¹

We see that:

t₁ = 1, r = 1/3

Sum of n terms:

Sₙ = t₁(1 - rⁿ)/(1 - r)
Sₙ = [1 - (1/3)ⁿ] / (1 - 1/3) = [1 - (1/3)ⁿ] / (2/3) = 3/2 [1 - (1/3)ⁿ]
Sₙ = 3/2 [1 - (1/3)ⁿ]

3 0

2 years ago

Divide £50 in the ratio of 1:4

NikAS [45]

Answer=10:40

Explanation:

Don’t know how to type the symbol in font of the 50 so I will substitute
£50=$50

So 1:4
Add it up
1+4=5

So 5 total units
$50=5
Divided by 5
$10=1 units

So 1:4=10:10 times 4=10:40

6 0

3 years ago

Yo can anyone help???

NeTakaya

Answer: 1/2

Hope this helps :)

5 0

2 years ago

A spherical balloon has a circumference of 25 cm.

ArbitrLikvidat [17]

Answer:

See below ↓↓

Step-by-step explanation:

Finding the radius

C = 2πr
25 = 2 x 3.14 x r
r = 25 / 6.28
r = 3.98 cm ≅ 4 cm

Surface Area

4πr²
4 x 3.14 x 4 x 4
3.14 x 64
200.96
201 cm²

Volume

4/3πr³ = 4πr² x r/3
201 x 4/3
67 x 4
268 cm³

4 0

1 year ago

What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10

jasenka [17]

Answer:

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

Solution:

The given expression is $(2 x-3 y)^{10}$

As per binomial theorem, we know,

$(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}$

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now $x^{5}\times y^5$ will be the 6 term where k =5

Now, $\mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}$

So, the coefficient of $x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right$ .

$10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252$

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

6 0

3 years ago