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8_murik_8 [283]
3 years ago
11

Can you help me on questions numbers 8 and 9 ASAP?

Mathematics
1 answer:
aleksandrvk [35]3 years ago
3 0
7. e and f
9. c.

sorry didn't understand 8

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7x + 5y - X + 2y + 3x
larisa [96]

Answer:

9x+7y

Step-by-step explanation:

please see the image that I have attached

8 0
2 years ago
Read 2 more answers
Which of the following best describes the graph below
vfiekz [6]

Answer:

It is a one-to-one function. C is the correct answer

Step-by-step explanation:

Since no x values are repeated on the Y axis, it is a one-to-one function. Option C is correct

3 0
2 years ago
If f(x)=2x+sinx and the function g is the inverse of f then g'(2)=
Alexxx [7]
\bf f(x)=y=2x+sin(x)
\\\\\\
inverse\implies x=2y+sin(y)\leftarrow f^{-1}(x)\leftarrow g(x)
\\\\\\
\textit{now, the "y" in the inverse, is really just g(x)}
\\\\\\
\textit{so, we can write it as }x=2g(x)+sin[g(x)]\\\\
-----------------------------\\\\

\bf \textit{let's use implicit differentiation}\\\\
1=2\cfrac{dg(x)}{dx}+cos[g(x)]\cdot \cfrac{dg(x)}{dx}\impliedby \textit{common factor}
\\\\\\
1=\cfrac{dg(x)}{dx}[2+cos[g(x)]]\implies \cfrac{1}{[2+cos[g(x)]]}=\cfrac{dg(x)}{dx}=g'(x)\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}

now, if we just knew what g(2)  is, we'd be golden, however, we dunno

BUT, recall, g(x) is the inverse of f(x), meaning, all domain for f(x) is really the range of g(x) and, the range for f(x), is the domain for g(x)

for inverse expressions, the domain and range is the same as the original, just switched over

so, g(2) = some range value
that  means if we use that value in f(x),   f( some range value) = 2

so... in short, instead of getting the range from g(2), let's get the domain of f(x) IF the range is 2

thus    2 = 2x+sin(x)

\bf 2=2x+sin(x)\implies 0=2x+sin(x)-2
\\\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}\implies g'(2)=\cfrac{1}{2+cos[2x+sin(x)-2]}

hmmm I was looking for some constant value... but hmm, not sure there is one, so I think that'd be it
5 0
2 years ago
Triangle ABC has vertices at A(−3, 4), B(4, −2), C(8, 3). The triangle is translated 4 units down and 3 units left. Which rule r
crimeas [40]

Option C: (x, y) \rightarrow(x-3, y-4) ; (5,-1) is the coordinates of C after translation.

Explanation:

The triangle ABC has vertices at A(−3, 4), B(4, −2), C(8, 3).

Also, given that the triangle is translated 4 units down and 3 units left.

We need to determine the coordinates of the vertex C after translation.

The triangle is shifted 4 units down means subtracting 4 units from the y - coordinate of the graph.

Thus, it can be written as y-4

Also, the triangle is shifted 3 units left means subtracting 3 units from the x - coordinate of the graph.

Thus, it can be written as x-3

Thus, the translation is given by

(x, y) \rightarrow(x-3, y-4)

The vertices of C after translation can be determined by

(8, 3) \rightarrow(8-3, 3-4)\implies (5,-1)

Thus, (x, y) \rightarrow(x-3, y-4) ; (5,-1) is the coordinates of C after translation.

Hence, Option C is the correct answer.

3 0
3 years ago
Read 2 more answers
Does anybody know the answer please.
wariber [46]

Answer:

The sign of each y-coordinate changed.

Step-by-step explanation:

This was a reflection over the x-axis.

If you look at point F, it is (-5, -1) the corresponding point F' is (-5,1).  Notice the numerical values of x and y are the same, but the sign of y flipped from negative to positive. The other four points all follow the same pattern.

8 0
3 years ago
Read 2 more answers
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