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3 years ago

Y = a(x - 2)(x + 4)

Mathematics

1 answer:

andriy [413]3 years ago

4 0

Answer:

Step-by-step explanation:

It just is

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If James make $7 per hour and Priya makes 20% more than James and Samantha makes 5% less than Priya how much does Samantha make

mixas84 [53]

Samantha makes $7.98 per hour

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3 years ago

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11. What is the location of the vertex of the parabola defined by f(x) = −3x2 − 18x − 35 and in what direction does the parabola

lbvjy [14]

11. The given parabola has equation: $f(x)=-3x^2-18x-35$

We complete the square to have the function in the vertex form: $f(x)=-3(x^2+6x)-35$

$f(x)=-3(x^2+6x+9)+3*9-35$

$f(x)=-3(x^2+6x+9)+27-35$

$f(x)=-3(x+3)^2-8$

The vertex is (-3,-8), the graph opens down because a=-3<0

Ans: B. Vertex: (−3, −8), opens downward

12. We know the graph of $y=x^2$ is a parabola that opens up and has its minimum point at the origin.

The range of this function is $y\ge 0$

A straight line that has its y-intercept below the x-axis (y=3x-6) will not intersect $y=x^2$ and hence will form a system with no solution.

Ans: D. y equals x squared, y equals 3x minus 6

14. We want to find the zeros of $x^2+21x=5x-63$

$x^2+21x-5x+63=0$

$x^2+16x+63=0$

The factored form is $(x+7)(x+9)=0$

$x=-7\:or\: x=-9$

Ans: C. x = −7, −9

15. The given quadratic expression is $6x^2-17x+10$

We split the middle term to obtain:

$6x^2-12x-5x+10=0$

We factor by grouping to get:

$6x(x-2)-5(x-2)=0$

$(x-2)(6x-5)=0$

Ans: D. 6x − 5

8 0

3 years ago

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Solve for x*<br> 55°<br> x + 74<br> I<br> 54°

tiny-mole [99]

The Answer Is 180. :)

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3 years ago

Is 3/4 bigger than 3/5

Svet_ta [14]

Yes, 3/4 is bigger than 3/5.
One way you can verify this is by drawing a bar model, and cut it into four. Color in three pieces.
Then, draw another bar model the same size as the first one, and cut it into five pieces.
Color in three pieces.
You can see that 3/4 has more shaded in area than 3/5.
Another way you can do this is by dividing the numerator by the denominator for both fractions.
Hope this helped.

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3 years ago

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Financial Mathematics Discussion Board Prompt:

yarga [219]

Answer:

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3 years ago