Do you know the answer?

A standard showerhead in Sonia's house dispenses 12 gallons of water per minute. Sonia changed this showerhead to an energy-savi

diamong [38]

Sonia saves a lot of water. To figure this out, you plug the number 8 into the equation, replacing it with the variable x. y = 3(8). Therefore, y=24. To find out how much water she saves, you have to also figure out how much water she was using for 8 minutes with the other shower head, the one that wastes the water. Since it dispenses 12 gallons per minute, you multiply that by 8 minutes and get 96. Subtract 24 from 96 and get 72. Which I think is your answer. Then again, I'm in high school so I most likely am wrong.

7 0

3 years ago

$1800 is invested at 4% compounded annually. Find the future value of the investment in 5 years. Find the interest that the inve

harina [27]

5 Years is 1800x1.04^5 = 2189.98
Interest is 389.98

8 0

3 years ago

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According to the University of Nevada Center for Logistics Management, 6% of all mer-

Fudgin [204]

Answer:

a) The point estimate of the proportion of items returned for the population of

sales transactions at the Houston store = 12/80 = 0.15

b) The 95% confidence interval for the proportion of returns at the Houston store = [0.0718 < p < 0.2282].

c) Yes.

We set an hypothesis and construct a test statistics. The test statistics result gives us:

Z calculated = 2.2545, and this gives us the p-value = 0.0121. We assumed 95% confident interval. Hence, the level of significance (α) = 5%. Conclusively, since the p-value ==> 0.0121 is less than (α) = 5%, the test is significant. Hence, the proportion of returns at the Houston store is significantly different from the returns for the nation as a whole.

Step-by-step explanation:

a) Point estimate of the proportion = number of returned items/ total items sold = 12/80 = 0.15.

b) By formula of confident interval:

CI(95%) = p ± Z* $\sqrt{\frac{p*(1-p)}{n} } = 0.15 \pm 1.96 *\sqrt{\frac{0.15*(1-0.15)}{80} }$ ,

CI(95%) = [0.0718 < p < 0.2282]

c) The hypothesis:

$H_{0}$ : The proportion of returns at the Houston store is not significantly different from the returns for the nation as a whole.

$H_{a}$ : The proportion of returns at the Houston store is significantly different from the returns for the nation as a whole.

The test statistics:

Z = $\frac{\hat{p} - p_{0}}{\sqrt{\frac{p*(1-p)}{n} }}$ , where $p_{0}$ is the proportion of nation returns.

Z calculated = 2.2545, and this gives us the p-value = 0.0121. We assumed 95% confident interval. Hence, the level of significance (α) = 5%. Conclusively, since the p-value ==> 0.0121 is less than (α) = 5%, the test is significant. Hence, the proportion of returns at the Houston store is significantly different from the returns for the nation as a whole.

6 0

3 years ago

Belle walks 7/10 mile each morning, and 1, 4/10 miles each evening.

kow [346]

Answer:

10.5 miles.

Step-by-step explanation:

If she walks 7/10 of a mile each morning, and 1, 4/10 of a mile each day, Belle walks a total of 2 1/10 of a mile each day (2.1) miles each day)

We can just multiply the amount of miles per day by 5, (2.1 x 5) and we get 10.5 miles total.

7 0

2 years ago

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