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kap26 [50]
3 years ago
6

Do you know the answer?

Mathematics
1 answer:
crimeas [40]3 years ago
8 0
I think the answer would be the thrid one

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Your school wants to take out an ad in the paper congratulating the basketball team on a successful​ season, as shown to the rig
iogann1982 [59]

Answer:

x_1 =-14.43 in, x_2 = 2.426in

Since the measurement can't be negative the correct answer for this case would be x =2.426 in

Step-by-step explanation:

Let's assume that the figure attached illustrate the situation.

For this case the we know that the original area given by:

A_i = 7 in *5 in = 35in^2

And we know that the initial area is a half of the entire area in red A_i = \frac{A_f}{2}, so then:

A_f = 2 A_ i =2*35 = 70

And we know that the area for a rectangular pieces is the length multiplied by the width so we have this:

70 = (x+7) (x+5)

We multiply both terms using algebra and the distributive property and we got:

70 =x^2 +12 x +5

And we can rewrite the expression like this:

x^2 +12 x -35 = 0

And we can solve this using the quadratic formula given by:

x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

Where a = 1, b =12 and c=-35 if we replace we got:

x = \frac{-12 \pm \sqrt{(12)^2 -4(1)(-35)}}{2*1}

And the two possible solutions are then:

x_1 =-14.43 in, x_2 = 2.426in

Since the measurement can't be negative the correct answer for this case would be x =2.426 in

3 0
3 years ago
A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m
photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

  • Mass of the car, v1 = 1500 kg
  • initial speed of car = 35 miles/h

                               =\dfrac{35\times 1609.34}{3600}\ m/s

                               = 15.64 m/s

Initial kinetic energy of the car is given by,

k_1\ =\ \dfrac{1}{2}.m.v_1^2

       =\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule

       = 183606.46 J

  • Final velocity of car v2 = 70 miles/hour

                                      =\dfrac{70\times 1609.34}{3600}

                                      = 31.29 m/s

So, final kinetic energy of car is given by

k_2\ =\ \dfrac{1}{2}.m.v_2^2

        =\ \dfrac{1}{2}\times 1500\times (31.29)^2

        = 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}

=>\ k_2\ =\ 4k_1                      

Hence, the kinetic energy will increase by 4 times.

7 0
3 years ago
Can someone help me plz
UNO [17]
It charged 2.2% per min
4 0
3 years ago
How much would it be $55 for every 15 shirts?
notsponge [240]

Answer:

<h3>$825 it would be that</h3>

Step-by-step explanation:

<h3>it would be that all you have to do is multiple 55×15=825</h3><h3>5×5</h3><h3>55 \times 15 = 825</h3>

8 0
3 years ago
Suppose the radius of a circle is 8 what is the diameter
sleet_krkn [62]
The diameter is 16 its double
8 0
3 years ago
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