1. The domain of a sqrt(x) is x > 0. So, L > 0.
2. The range of a S(x) = sqrt(x) is S(x) > 0 for all valid x > 0.
Answer:
7/3
Explanation:
The slope of the line is equal to the rise/run, or in other words, the number of units the line travels upwards over the number of units the line travels to the right.
We can identify the slope using any two points on the line. Here, we can use the two points that are marked on the picture. The second point is 7 units above the first and 3 units to the right of the first, so the slope of the line is equal to 7/3.
Another way to calculate the slope of the line is the use this formula:
(y2-y1)/(x2-x1)
The first point is at the coordinate (1,-4) and second point is at the coordinate (4,3). When we plug these two coordinates into the equation, we get this:
(y2-y1)/(x2-x1)
->(3-(-4))/(4-1)
When we simply the fraction, we would get 7/3 and that would give us the slope.
I hope this helps!
If two sides of a right triangle are x and y, the hypotenuse, h is:
h^2=x^2+y^2, in this case x and y are 39 and 52 respectively so:
h^2=39^2+52^2
h^2=1521+2704
h^2=4225
h=√4225
h=65 in
So the hypotenuse is 65 inches.
