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If line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23
The line AB and BC are intersecting at point B.
Ray BD bisect the angle ABC
∠ABD = x+8 degrees
∠ABD=∠DBC = x+8
Because the ray BD bisect the ∠ABC, so ∠ABD and ∠DBC will be equal
∠ABD+∠DBC= 4x-30 degrees
Because both are vertically opposite angles
Substitute the values in the equation
x+8 + x+8 = 4x-30
2x+16 = 4x-30
2x-4x = -30-16
-2x = -46
x = 23
Hence, if line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23
The complete question is
Line AB and BC are intersecting at point B and ray BD bisect the angle ABC. What is the value of x?
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N is -4 because -4x2=-8 and -8+3=-5
If it's a negative exponent for example -6 the answer would be 1/x^-6. So if x is 10. Then 10^-6 is equal to 1/10^6 (One over ten to the power of 6 or One divided by 10 to the power six)
Answer:
x = 3/7
Step-by-step explanation:
Step 1:
6 - 2x = 3 + 5x Equation
Step 2:
6 = 3 + 7x Add 2x on both sides
Step 3:
3 = 7x Subtract 3 on both sides
Answer:
x = 3/7 Divide
Hope This Helps :)