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2 years ago

10 hundredths in standard form.

Mathematics

2 answers:

strojnjashka [21]2 years ago

5 0

Answer:

1×10^3

Hope it helps u.ok

Aneli [31]2 years ago

4 0

.10 I hope that that helps you :)

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You deposit $260 every six months into an account earning 4.1% interest compounded semiannually.

butalik [34]

Answer:

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Step-by-step explanIation:

subs to sir joel his playing blockman go

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2 years ago

Find the value of x in the triangle shown below.<br> x = ___°

blagie [28]

I think x= 70 rights

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2 years ago

Which expression is equivalent to 2 (14x-37+28x+12.2-5y-17.5)?

ziro4ka [17]

Answer:

A. 84x - 16y - 10.6

Explanation:

$\sf \rightarrow 2(14x-3y+28x+12.2-5y-17.5)$

$\sf \rightarrow 2 (42x-8y-5.3)$

apply distributive method: a(b + c) = ab + ac

$\sf \rightarrow 2 (42x) -2(8y)-2(5.3)$

$\sf \rightarrow 84x -16y-10.6$

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1 year ago

100 POINTS AND BRAINLIEST

zysi [14]

Answer:

8 square units and $\frac{40}{3}$ square units

Step-by-step explanation:

The area of the triangle ABC is 24 square units.

1. Triangles ABC and FBG are similar with scale factor $\frac{1}{3},$ then

$\dfrac{A_{\triangle FBG}}{A_{\triangle ABC}}=\dfrac{1}{9}\Rightarrow A_{\triangle FBG}=\dfrac{1}{9}\cdot 24=\dfrac{8}{3}\ un^2.$

2. Triangles ABC and DBE are similar with scale factor $\frac{2}{3},$ then

$\dfrac{A_{\triangle DBE}}{A_{\triangle ABC}}=\dfrac{4}{9}\Rightarrow A_{\triangle DBE}=\dfrac{4}{9}\cdot 24=\dfrac{32}{3}\ un^2.$

3. Thus, the area of the quadrilateral DFGE is

$A_{DFGE}=A_{\triangle DBE}-A_{\triangle FBG}=\dfrac{32}{3}-\dfrac{8}{3}=8\ un^2.$

and the area of the quadrilateral ADEC is

$A_{ADEC}=A_{\triangle ABC}-A_{\triangle DBE}=24-\dfrac{32}{3}=\dfrac{40}{3}\ un^2.$

4 0

2 years ago

Read 2 more answers

Two numbers that differ by 46

Reil [10]

the complete question is

Find two numbers whose difference is 46 and whose product is a minimum

Let

x------->larger number

y-------> smaller number

P-------> product of the two numbers

we know that

$x-y=46\\ y=x-46$ -----> equation 1

$P=x*y$ -----> equation 2

substitute equation 1 in equation 2

$P=x*[x-46]\\ P=x^{2} -46x$

using a graph tool

see the attached figure

Find the value of x for that the product P is a minimum

the vertex is the point $(23,-529)$

that means, for $x=23$

the product is a minimum $P=-529$

find the value of y

$y=x-46\\ y=23-46\\ y=-23$

therefore

the answer is

the numbers are $23$ and $-23$

7 0

2 years ago

Read 2 more answers