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kaheart [24]
3 years ago
8

Write an expression to represent: The sum of ten and the quotient of a number x and 6.

Mathematics
1 answer:
Minchanka [31]3 years ago
8 0
Let us break it down. A sum of ten. That is just 

+10

Then, we will add that to the quotient (which is the number after dividing) of a number x and 6. We can write that as 

+ x/6

The slash means division here. Thus your final answer is 


10 + x/6
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H(x) = 3x-4 what is h(6)
lina2011 [118]

Answer:

14

Step-by-step explanation:

3*6=18

18-4=14

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For all values of x f(x)
Firlakuza [10]

Answer:

f(g(5)) = 64

g(f(5)) = 28

Step-by-step explanation:

Given  that f(x) = x^2 and g(x) = x+3

f(g(x) = f(x+3)

f(x+3) = (x+3)^2

f(g(x)) = (x+3)^2

f(g(5)) = (5+3)^2

f(g(5)) = 8^2

f(g(5)) = 64

b) g(f(x)) = g(x^2)

g(f(x)) = x^2 + 3

g(f(5)) = 5^2 +3

g(f(5)) = 25 + 3

g(f(5)) = 28

Hence the value of g(f(5)) is 28

5 0
3 years ago
What is 30% of 70? Please help.
garik1379 [7]
Hi lovely,

The answer you're looking for is 21.
3 0
3 years ago
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Suppose the weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams. The weights
user100 [1]

Answer:

a) 0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b) The weight that 80% of the apples exceed is of 78.28g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams.

This means that \mu = 85, \sigma = 8

a. Find the probability a randomly chosen apple exceeds 100 g in weight.

This is 1 subtracted by the p-value of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 85}{8}

Z = 1.875

Z = 1.875 has a p-value of 0.9697

1 - 0.9696 = 0.0304

0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b. What weight do 80% of the apples exceed?

This is the 100 - 80 = 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.

Z = \frac{X - \mu}{\sigma}

-0.84 = \frac{X- 85}{8}

X - 85 = -0.84*8

X = 78.28

The weight that 80% of the apples exceed is of 78.28g.

5 0
3 years ago
Solve this the link is down below
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There is no link here
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