Solve for x
x-4=11
x=11+4
x=15
Answer:
Step-by-step explanation:
<u>Standard for of quadratic equation:</u>
<u>We have </u>
<u>Sum of the roots </u>
- x₁ + x₂ = - b/a = -(-5)/2 = 2.5
<u>Product of the roots </u>
<u>We have:</u>
<u>The square of the above is:</u>
- (x₁ - x₂)² = (x₁ + x₂)² - 4x₁x₂
<u>Substitute known values and solve for c:</u>
- 0.25² = (2.5)² - 4(c/2)
- 2c = 6.25 - 0.0625
- 2c = 6.1875
- c = 3.09375
X=10 and X=3/4 basically it’s whatever X equals to make the inside the parentheses equal zero. So if I were to plug 10 into the first parentheses you’d have 10-10 which equals zero. Also the zero has to the the opposite sign of what’s in the parentheses. So if -10 is in the parentheses then the zero has to be the opposite so positive 10.
y - y1 = m(x + x1)
m = (y2 - y1)/(x2 - x1) = (-6 - 2)/(-1 - 5) = -8/(-6) = 4/3
y - 2 = 4/3(x - 5) is a possible answer
y + 6 = 4/3(x + 1) is also a possible answer
Remember
∛(ab)=(∛a)(∛b)
also
i¹=i
i²=-1
i³=-i
i⁴=1
so
∛-2i=(∛2)(∛-i)=(∛2)(i)=i∛2
