9514 1404 393
Answer:
9.5°, yes
Step-by-step explanation:
The relevant trig relation is ...
Tan = Opposite/Adjacent
The distance opposite the angle of elevation is the plane's height, 500 m. The distance adjacent to the angle of elevation is the horizontal distance to the plane, 3 km = 3000 m. Then the angle is found from ...
tan(α) = 500/3000 = 1/6
α = arctan(1/6) ≈ 9.46°
The plane is approaching at an angle of 9.46°. It is safe to land, since that angle is less than 15°.
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<em>Additional comment</em>
The usual descent angle for most commercial air traffic is 3°. Some airport geography demands it be different (steeper). A higher descent angle can put undue stress on the landing gear.
The measure of angle P is 29 degrees
The sum of an interior angle of a triangle is 180 degrees. Given the following parameters:
Taking the sum and equating to 180 degrees:
m<M + m<N + m<P = 180 degrees
15x + 5 + 3x + 2 + 5x - 11 = 180
23x - 4 = 180
23x = 184
x = 184/23
x = 8
Get the measure of m<P
m<P = 5x - 11
m<P = 5(8) - 11
m<P = 40 - 11
m<P = 29 degrees
Hence the measure of angle P is 29 degrees
Learn more on angles here: brainly.com/question/25770607
The answer i think is the rate
Answer:
height = 12 cm
Step-by-step explanation:
Parallelogram 1:
Area = base *height = 20 * 15 = 300 sq. cm
Area of parallelogram 2 = area of parallelogram 1
25 * height = 300
height = 300/25
height = 12 cm
-6/7p+1/7 um Idk what you wanted me to do but I added -4/7p with -2/7p
