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Elan Coil [88]
3 years ago
13

When a number is decreased by 20% of itself, the result is 128. What is the number?

Mathematics
1 answer:
andreev551 [17]3 years ago
8 0
128 x 5= 640 which is 100% 640/128= 20
640 x 20%= 128

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Please help me
dusya [7]
3(4x - 2) = 2(6x - 3)

12x - 6 = 12x - 6

Add 6 on both sides

12x = 12x

Divide by 12 on both sides

x = x

That means this has infinite solutions. Your answer is B.
4 0
3 years ago
Read 2 more answers
Equation of a line that best fits the points (-4,10)(-1,5) (2,-1) (3,-6) (5,-7)
Slav-nsk [51]

Answer:

-2.02+2.22=trendline

8 0
3 years ago
I think it’s b but I may be wrong
leonid [27]

Answer:

D, not B

Step-by-step explanation:

So using Pythagorean Theorem:

C^{2} =A^{2} +B^{2} \\x^{2} =144+265\\x^{2} =400\\x=20

Yep, It's not B, But D.

Hope this helps!

Stay Safe!

6 0
3 years ago
4-7x=1-6x can someone please solve and show the work :)
vekshin1

Answer:

x = 3

Step-by-step explanation:

Simplifying

4 + -7x = 1 + -6x

Solving

4 + -7x = 1 + -6x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '6x' to each side of the equation.

4 + -7x + 6x = 1 + -6x + 6x

Combine like terms: -7x + 6x = -1x

4 + -1x = 1 + -6x + 6x

Combine like terms: -6x + 6x = 0

4 + -1x = 1 + 0

4 + -1x = 1

Add '-4' to each side of the equation.

4 + -4 + -1x = 1 + -4

Combine like terms: 4 + -4 = 0

0 + -1x = 1 + -4

-1x = 1 + -4

Combine like terms: 1 + -4 = -3

-1x = -3

Divide each side by '-1'.

x = 3

Simplifying

x = 3

5 0
3 years ago
A quality control inspector samples 2 computer chips from a box containing 13 computer chips. If the box contains 3 defective ch
elena-14-01-66 [18.8K]

Answer:

The number of ways to select a sample of 2 computer chips so that at least one of the chips is defective is 33 ways.

Step-by-step explanation:

The box contains 13 computer chips. Of these 13 chips 3 are defective and 10 are good.

A quality control inspector samples 2 computer chips.

The number of ways to select at least 1 defective chip is:

n (At least 1 defective chip) = n (1 defective chip) + n (2 defective chips)

The number of ways to select 1 defective chip is: {3\choose 1}{10\choose 1}=3\times10=30 ways.

The number of ways to select 2 defective chips is:{3\choose 2}{10\choose 0}=3\times1=3 ways.

n (At least 1 defective chip) = n (1 defective chip) + n (2 defective chips)

                                             = 30 + 3

                                             = 33

Thus, the number of ways to select a sample of 2 computer chips so that at least one of the chips is defective is 33 ways.

5 0
3 years ago
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