Answer:
see the attachment
Step-by-step explanation:
We assume that the question is interested in the probability that a randomly chosen class is a Friday class with a lab experiment (2/15). That is somewhat different from the probability that a lab experiment is conducted on a Friday (2/3).
Based on our assumption, we want to create a simulation that includes a 1/5 chance of the day being a Friday, along with a 2/3 chance that the class has a lab experiment on whatever day it is.
That simulation can consist of choosing 1 of 5 differently-colored marbles, and rolling a 6-sided die with 2/3 of the numbers being designated as representing a lab-experiment day. (The marble must be replaced and the marbles stirred for the next trial.) For our purpose, we can designate the yellow marble as "Friday", and numbers greater than 2 as "lab-experiment".
The simulation of 70 different choices of a random class is shown in the attachment.
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<em>Comment on the question</em>
IMO, the use of <em>70 trials</em> is coincidentally the same number as the first <em>70 days</em> of school. The calendar is deterministic, so there will be exactly 14 Fridays in that period. If, in 70 draws, you get 16 yellow marbles, you cannot say, "the probability of a Friday is 16/70." You need to be very careful to properly state the question you're trying to answer.
Let’s take the number .666666 repeating
If we turn it into a fraction it’s 2/3.
It doesn’t matter how many numbers repeat to write a fraction.
Hope this helps.
The width of the laptop is 6 inches long.
1) a=5+√29 or a=5−√29
2) x=1 or x=−21
3) x=4 or x=6
4) x=9+√146 or x=9−√146
Hopefully that helps you ❤
Answer:
Step-by-step explanation:
Ruth's salary is s(j), where s represents salary and j the number of jars she sells.
At the very beginning, she receives $50. Only answer 'd' could be correct.
But also, the equation has the variable part 0.65j, or
$0.65j, which is directly proportional to the unit price of the jars of jelly.
*
Summing up the fixed and variable parts, we get
s = $50 + ($0.65j), or s = $50 + ($0.65/jar)j This is Answer D.