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lara31 [8.8K]
3 years ago
9

The result of 1/12×0,30 isplease answer​

Mathematics
1 answer:
Archy [21]3 years ago
5 0

Answer:

0.025

Step-by-step explanation:

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3 years ago
Halim makes a profit of 120% on his cost price by selling a pair of shoes of $45. i) Find the cost pricer of the pair of shoes i
Rus_ich [418]

Answer:

a. $20.45

b. $24.55

c. $4.55

Step-by-step explanation:

In this question, we are asked to calculate the cost price and profit or loss selling a pair of shoes.

we proceed as follows

Firstly, we want to find the cost price given the selling price and the mark up percentage.

mathematically;

profit =( selling price - cost price)/cost price * 100%

here our profit is 120% with the cost price being $45. we plug these values

120 = 45-cp/cp * 100%

120cp = 100(45-cp)

120cp = 4500 -100cp

220cp = 4500

cp = 4500/220 = $20.45

His profit is selling price - cost price = 45 - 20.45 = $24.55

His profit selling same shoe for $25 is 25-20.45 = $4.55

4 0
3 years ago
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Misha Larkins [42]

Answer:

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8 0
3 years ago
A function passes through the points (2,9) and (7,34). What are its rate of change and initial value?
Bess [88]

Answer:

The rate of change: 1/5

Initial value: (0,-1)

Step-by-step explanation:

The rate of change is easily 5/25, we just have to simplify it to 1/5.

To get the intial value, just subtract (2,9) by the rate of change twice.

5 0
3 years ago
The radioactive isotope radium has a half-life of 1,600 years. The mass of a 100-gram sample of radium will be______ grams after
Olenka [21]
To solve this we are going to use the half life equation N(t)=N_{0} e^{( \frac{-0.693t}{t _{1/2} }) }
Where:
N_{0} is the initial sample
t is the time in years
t_{1/2} is the half life of the substance
N(t) is the remainder quantity after t years 

From the problem we know that:
N_{0} =100
t=200
t_{1/2} =1600

Lets replace those values in our equation to find N(t):
N(200) =100e^{( \frac{(-0.693)(200)}{1600}) }
N(200)=100e^{( \frac{-138.6}{1600} )}
N(200)=100e^{-0.086625}
N(200)=91.7

We can conclude that after 1600 years of radioactive decay, the mass of the 100-gram sample will be 91.7 grams.

8 0
3 years ago
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