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Inessa [10]
3 years ago
14

Find the 14th term of the arithmetic sequence whose common difference is d=9 and whose first term is an = 2.

Mathematics
1 answer:
jeyben [28]3 years ago
6 0

9514 1404 393

Answer:

  119

Step-by-step explanation:

Put the given values in the formula for the general term, and do the arithmetic.

  an = a1 +d(n -1) . . . . . first term a1, common difference d

  a14 = 2 +9(14 -1) = 119

The 14th term is 119.

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I NEED HELP ASAP WILL GIVE BRAINLIEST FOR ALL 3
Viefleur [7K]

2) i don't know answer for 2, but i know that it isn't right triangle because from Pythagoras' Theory we know that for right triangle: a^2 + b^2 = c^2 but in this triangle 30^2 + 38^2 ≠ 54^2

3) from Pythagoras' theory we know that the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares on the other two sides: a^2 + b^2 = c^2

we have to check this in this triangle:

12^2 + 16^2 = 400

√400 = 20

we know that third side of this triangle is 20 so this triangle is right triangle

3) in square all sides are same so If a is the one side of the square then area of this square will be a x a = 242

a^2 = 242

so from Pythagoras' theorem we can found the diagonal:

a^2 + a^2 = c^2 ( c is hypothenuse)

242 + 242 = c^2

484 = c^2

c = 22

hope it's correct and it'll help you :)

8 0
3 years ago
Is absolute value of -998​
Nikitich [7]

Answer:

998.

Step-by-step explanation:

Just get rid of the negative sign

7 0
3 years ago
Read 2 more answers
Find the measure of the arc or angle indicated.<br> #3 AND #4 please<br> will give brainliest
Anika [276]

Answer:

3=180

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Step-by-step explanation:

7 0
3 years ago
I need help with this
Anna11 [10]
Heyy!
Here’s ur answer, hope it helps-
Area of parallelogram= base*heigh
=15*20
=300
Therefore your answer is 300 square units-
:)
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3 years ago
Ms. Terry's class is hosting a fundraising
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You do not have enough information because you need to know how many students are in the class to be able to divide them into 4 equal groups we do know that it has to be a positive integer that can be evenly divided by 4
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4 years ago
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