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2 years ago

1. The fractions

Mathematics

1 answer:

sergey [27]2 years ago

3 0

Answer:

3/7 =12/n

3n=7×12

3n=84

n=84÷3

n=28

3/7= t/21

3×21=7t

63=7t

t=63÷7

t=9

3/7 =k-1/2k+10

3(2k+10)=7(k-1)

6k+30=7k-7

k=37

Step-by-step explanation:

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What is -2y + 10 + 2y - 8 simplified

Andru [333]

Answer:

Step-by-step explanation:

-2y + 2y = 0

10 - 8 = 2

8 0

3 years ago

Read 2 more answers

3. Write an equation of a line that is perpendicular to the line x – 2y = 8.

xenn [34]

Answer:

y=0.5x+40

Step-by-step explanation:

Copy the equation.

x-2y=8

Subtract x from both sides.

-2y=-x-8

Divide both sides by -2.

y=0.5x+4

Now we know the slope is 0.5.

Any line with a slope of 0.5 will be perpendiculr to the original line.

One that you can use is y=0.5x+40.

7 0

3 years ago

Help plzzzzzzzzzzzzzzzzzzzzz

prohojiy [21]

Answer:

c = ${\boxed{\boldsymbol{29}}}$ km

Step-by-step explanation:

Here's the required formula to find the missing side of triangle by pythagoras theorem :

${\longrightarrow{\pmb{\sf{{(a)}^{2} + {(b)}^{2} = {(c)}^{2}}}}}$

$\purple\star$ a = 20 km
$\purple\star$ b = 21 km
$\purple\star$ c = ?

Substituting all the given values in the formula to find the third side of triangle :

$\begin{gathered} \quad{\longrightarrow{\sf{{(a)}^{2} + {(b)}^{2} = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{{(20)}^{2} + {(21)}^{2} = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{(20 \times 20) + (21 \times 21) = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{(400) + (441) = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{400 + 441 = {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{841= {(c)}^{2}}}} \\ \\ \quad{\longrightarrow{\sf{c = \sqrt{841}}}} \\ \\ \quad{\longrightarrow{\sf{\underline{\underline{\purple{c = 29 \: km}}}}}}\end{gathered}$