2a^2b^3(4a^2+3ab^2-ab)=?
<span>
is what I presume you actually meant. </span>
<span>
Pull out the common factors of (4a^2+3ab^2-ab) and you will get </span>
<span>
a(4a+3b^2 -b) </span>
Substitute this back into the original equation and you get
<span>
2a^2b^3[a(4a+3b^2-b)] = </span>
2a^3b^3(4a+3b^2-b) =
<span>2a^3b^3(4a-b+3b^2)
</span>
Answer:
There is an error in the question.
All angles in an equilateral triange are 60º
1. how many times 47 fits on 985? 20×47=940
try higher: 47×21=987. So use 20. subtract 985-940=45. how many times does 47 fit on 45? 0 so the answer should be 20 remainder 45
Answer:
18=1/12
Step-by-step explanation:
you take both fractions and multiply them to get 1/12
