Answer:
$220.18
Step-by-step explanation:
The amount A(n) accrued for P dollars saved at r% annual interest for a period of n years compounded k times is derived using the formula:

In Jayden's case:
- A(n)=$400
- r=12%=0.12
- n=5 years
- k=12 Months
We want to determine the amount Jayden put in the savings account.


Jayden earned $220.18 from doing odd jobs.
17-9 = 8
8 is your answer.
$58-$25=x this would be the equation i believe
Answer:
Step-by-step explanation:
The given polynomial is :
p(x) = 5-10x
We need to find the zeros of the above polynomial. To find it, put p(x) = 0
5-10x = 0
Subtract 5 from both sides
5-10x-5=0-5
-10x=-5
or
10x=5
Divide both sides by 10.
x = 0.5 = 1/2
Hence, the zeros of the polynomial is 1/2.
Answer:
The amount of money in Enid bank account can be written as a linear equation.
Ye = Xe + $4*m
where Ye is the money that Enid has in her account, m is the number of months that have passed since she opened it, and Xe is the initial deposit.
For Jim, the equation is similar:
Yj = Xj + $3*m
where Yj and Xj are similar as above.
Between May 15 and December 31 of the same year, we have 7 months (where i am counting December because the deposit is made in the first day of the month).
Then we have that:
Ye = $72 = Xe + $4*7 = Xe + $28
Xe = $72 - $28 = $44
So in May 15, Enid deposited $44.
For Jim we have:
Yj = $72 = Xj + $3*7 = Xj + $21
Xj = $72 - $21 = $51
So in May 15, Jim deposited $51.