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Fittoniya [83]
2 years ago
14

8x + y 17 4x + 3y - 31

Mathematics
2 answers:
Vladimir [108]2 years ago
7 0

1) 8x+y\cdot \:17:\quad 8x+17y

2) 4x+3y-31:\quad 4x+3y-31

klemol [59]2 years ago
3 0

Answer:Please see the above explanation . Hope it helps you . Please mark me brainlist please.

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Please help me with the below question.
Snezhnost [94]

6a. By the convolution theorem,

L\{t^3\star e^{5t}\} = L\{t^3\} \times L\{e^{5t}\} = \dfrac6{s^4} \times \dfrac1{s-5} = \boxed{\dfrac5{s^4(s-5)}}

6b. Similarly,

L\{e^{3t}\star \cos(t)\} = L\{e^{3t}\} \times L\{\cos(t)\} = \dfrac1{s-3} \times \dfrac s{1+s^2} = \boxed{\dfrac s{(s-3)(s^2+1)}}

7. Take the Laplace transform of both sides, noting that the integral is the convolution of e^t and f(t).

\displaystyle f(t) = 3 - 4 \int_0^t e^\tau f(t - \tau) \, d\tau

\implies \displaystyle F(s) = \dfrac3s - 4 F(s) G(s)

where g(t) = e^t. Then G(s) = \frac1{s-1}, and

F(s) = \dfrac3s - \dfrac4{s-1} F(s) \implies F(s) = \dfrac{\frac3s}{\frac{s+3}{s-1}} = 3\dfrac{s-1}{s(s+3)}

We have the partial fraction decomposition,

\dfrac{s-1}{s(s+3)} = \dfrac13 \left(-\dfrac1s + \dfrac4{s+3}\right)

Then we can easily compute the inverse transform to solve for f(t) :

F(s) = -\dfrac1s + \dfrac4{s+3}

\implies \boxed{f(t) = -1 + 4e^{-3t}}

6 0
1 year ago
The sum of two numbers is no more than 28. Let x represent the first number, and let y represent the second number. Which
Sphinxa [80]
The answer is the first one
7 0
2 years ago
Solve each equation for p.<br> P+3/m=-1
Otrada [13]

Answer:

P= -m-3

I hope this helps!

3 0
3 years ago
Could someone please help me solve this?
Ber [7]

the answer to your equation is

n=40

3 0
3 years ago
Will pay $5 to whoever solves this :)
Nataly [62]
Can u send a better picture pls
8 0
3 years ago
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