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2 years ago

8x + y 17 4x + 3y - 31

Mathematics

2 answers:

Vladimir [108]2 years ago

7 0

1) $8x+y\cdot \:17:\quad 8x+17y$

2) $4x+3y-31:\quad 4x+3y-31$

klemol [59]2 years ago

3 0

Answer:Please see the above explanation . Hope it helps you . Please mark me brainlist please.

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Please help me with the below question.

Snezhnost [94]

6a. By the convolution theorem,

$L\{t^3\star e^{5t}\} = L\{t^3\} \times L\{e^{5t}\} = \dfrac6{s^4} \times \dfrac1{s-5} = \boxed{\dfrac5{s^4(s-5)}}$

6b. Similarly,

$L\{e^{3t}\star \cos(t)\} = L\{e^{3t}\} \times L\{\cos(t)\} = \dfrac1{s-3} \times \dfrac s{1+s^2} = \boxed{\dfrac s{(s-3)(s^2+1)}}$

7. Take the Laplace transform of both sides, noting that the integral is the convolution of $e^t$ and $f(t)$ .

$\displaystyle f(t) = 3 - 4 \int_0^t e^\tau f(t - \tau) \, d\tau$

$\implies \displaystyle F(s) = \dfrac3s - 4 F(s) G(s)$

where $g(t) = e^t$ . Then $G(s) = \frac1{s-1}$ , and

$F(s) = \dfrac3s - \dfrac4{s-1} F(s) \implies F(s) = \dfrac{\frac3s}{\frac{s+3}{s-1}} = 3\dfrac{s-1}{s(s+3)}$

We have the partial fraction decomposition,

$\dfrac{s-1}{s(s+3)} = \dfrac13 \left(-\dfrac1s + \dfrac4{s+3}\right)$

Then we can easily compute the inverse transform to solve for f(t) :

$F(s) = -\dfrac1s + \dfrac4{s+3}$

$\implies \boxed{f(t) = -1 + 4e^{-3t}}$

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1 year ago

The sum of two numbers is no more than 28. Let x represent the first number, and let y represent the second number. Which

Sphinxa [80]

The answer is the first one

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2 years ago

Solve each equation for p.<br> P+3/m=-1

Otrada [13]

Answer:

P= -m-3

I hope this helps!

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3 years ago

Could someone please help me solve this?

Ber [7]

the answer to your equation is

n=40

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3 years ago

Will pay $5 to whoever solves this :)

Nataly [62]

Can u send a better picture pls

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3 years ago