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zaharov [31]
3 years ago
11

ERROR ANALYSIS Describe and correct the error in solving the equation.

Mathematics
1 answer:
Crank3 years ago
6 0

the error was that you did not use the distributive property in 4(x-2)

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PLEASE HELP
pogonyaev

Answer:

b and c

Step-by-step explanation:

both slopes are 2/3

6 0
3 years ago
How much do subtract from 37/6 to make 6
choli [55]
37÷6
=6.1666666667
- 0.1666666667
=6
4 0
3 years ago
Jan pick 3/4 of a gallon of strawberries in a half an hour. If she keeps picking strawberries at the same rate, how many gallons
krek1111 [17]
2 divided by 1/2
2 x 2/1 = 4
3/4 x 4/1 = 12/3
12/3 = 4
4 gallons, Hope this helps!
8 0
3 years ago
Read 2 more answers
If Tammy takes out a discounted loan for $850 at a simple interest rate of 12%, but only receives $800 into her bank account, wh
Vikki [24]

Answer : The duration of the loan is, 6 months

Step-by-step explanation :

First we have to determine the discounted money.

Discounted money = $850 - $800 = $50

Thus, interest = $50

Now we have to determine the time of loan.

Formula used :

S.I=\frac{PRT}{100}

where,

P = principle

R = interest rate

T = time

S.I = simple interest

Now put all the given values in the above formula, we get:

For 1 year : \$50=\frac{(\$850)\times (12)\times T}{100}

For 12 months : \$50\times 12=\frac{(\$850)\times (12)\times T}{100}

T=5.88month\approx 6month

Thus, the duration of the loan is, 6 months

3 0
3 years ago
I'm genuinely lost in any problems like this and my teachers are no help, I need help doing exponents in general, everything to
Stolb23 [73]

Answer:

See below.

Step-by-step explanation:

4)

So we have the expression:

(-6n^{-3})^2

We can use the power of a product property, where:

(ab)^n=a^n\cdot b^n

So:

=(-6)^2\cdot(n^{-3})^2

For the left, -6 squared is the same as -6 times -6. This equals positive 36.

For the right, we can use the power of a power property. The property says that:

(a^n)^k=a^{nk}

So:

(n^{-3})^2=n^{(-3)(2)}\\=n^{-6}

So, all together, we have:

=(-6)^2\cdot(n^{-3})^2\\=36n^{-6}

6)

We have the expression:

-\frac{3x^0}{x^4}

First, note that anything to the zeroth power (except for 0) is 1, thus, x^0 is also 1. Simplify:

=-\frac{3}{x^4}

And that's the simplest we can do :)

Notes for 6)

We <em>can</em> put the x^4 to the numerator. Recall that when you put an exponent to opposite side, you put a negative. In other words:

x^n=\frac{1}{x^{-n}}

And vice versa:

\frac{1}{x^{-n}}=x^n

So, we can write the above as:

=-\frac{3}{x^4}\\=-\frac{3}{x^{-(-4)}}\\=-3x^{-4}

However, traditionally, we want only positive exponents, so this wouldn't be correct.

4 0
3 years ago
Read 2 more answers
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