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2 years ago

A piece of cardboard is 24 centimeters long and 15 centimeters wide. What is the area?

Mathematics

2 answers:

galina1969 [7]2 years ago

8 0

$24*15=

360$

360 square centimeters

Jet001 [13]2 years ago

7 0

24 x 15 = 360 Length x width

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-1/5y+7=7 What is the value of y?

liq [111]

The answer is y=0

See the attached photo for details

Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.

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2 years ago

Fernando and Roger are both in an art class. Fernando has created 40 projects in class this year. Fernando has created five time

Natali [406]

40x5= 200 I'm not sure who created five times more projects than the other, but whoever did, created 200 projects.

3 0

3 years ago

The length of each side of a regular pentagon is increased by 8 inches, so the perimeter is now 65 inches. What is the original

evablogger [386]

Here as the Pentagon is regular so it's all sides will be of equal length . And if we assume It's each side be s , then it's perimeter is going to be (s+s+s+s+s) = 5s.And as here , each side is increased by 8 inches and then it's perimeter is 65 inches , so we got that it's side after increament is (s+8) inches and original length is s inches . And if it's each side is (s+8) inches , so it's perimeter will be 5(s+8) and as it's equal to 65 inches . So , 5(s+8) = 65

${:\implies \quad \sf 5(s+8)=65}$

${:\implies \quad \sf 5s+5\times 8=65}$

${:\implies \quad \sf 5s+40=65}$

${:\implies \quad \sf 5s=65-40}$

${:\implies \quad \sf 5s=25}$

${:\implies \quad \sf s=\dfrac{25}{5}=5}$

${:\implies \quad \bf \therefore \quad \underline{\underline{s=5\:\: Inches}}}$

As we assumed the original side to be s .

Hence, the original side's length 5 inches 

8 0

2 years ago

I need help with this ASAP plzzzzz

miss Akunina [59]

Answer:

23. $\frac{4\sqrt{3} }{3}$

24. $\frac{7\sqrt{3}}{3}$

25. $6\sqrt{3}$

26. $\frac{10\sqrt{3} }{3}$

27. $14$

28. $4\sqrt{3}$

Step-by-step explanation:

To solve these i used SOHCAHTOA

$sin=\frac{opposite}{adjacent}\\ cos=\frac{adjacent}{hypotenuse} \\tan=\frac{opposite}{adjacent}$

23.

Find the missing side using Tangent

$tan(30)=\frac{x}{4}$

$4*tan(30)=x$

$\frac{4\sqrt{3} }{3}$

24.

Find the missing side using Tangent

$tan(30)=\frac{x}{7}$

$7*tan(30)=x$

$\frac{7\sqrt{3}}{3}$

25.

Find the missing side using Tangent

$tan(30)=\frac{x}{18}$

$18*tan(30)=x$

$6\sqrt{3}$

26.

Find the missing side using Tangent

$tan(30)=\frac{x}{10}$

$10*tan(30)=x$

$\frac{10\sqrt{3} }{3}$

27.

Find the missing side using Tangent

$tan(30)=\frac{x}{14\sqrt{3} }$

$(14\sqrt{3}) *tan(30)=x$

$14$

28.

Find the missing side using Tangent

$tan(30)=\frac{x}{12}$

$12*tan(30)=x$

$4\sqrt{3}$

5 0

3 years ago

Julia has 4 gallons 2 quarts of water.Ally needs the same amount of water but only has 12 quarts.How much more water does Ally n

ozzi

Ok so what do we know :

4 quarts = 1 gal
Julia has 4gal and 2 quarts or 18 quarts
ally has 12 quarts

so if julia has 18 quarts and ally has 12 that means that ally needs 6 more quarts (or 1gal 2 quarts) so that she and julia can have the same amount

8 0

3 years ago

Read 2 more answers