35000, rounding down from five.
Answer:
The area of the parallelogram is:_______________________________________________________ in² = 1174 ⅛ in² = 1174.125 in² .
_______________________________________________________Explanation:_______________________________________________________Area of a parallelogram:
_______________________________________________________ A = base * height = b * h ;
From the figure (from the actual "question"):
_______________________________________ b = 50.5 in.
h = 23.25 in.
____________________________________________________________Method 1) A = b * h =
= (50.5 in) * (23.25 in) = 1174.125 in² ; or, write as: 1174 <span>⅛ .
</span>
____________________________________________________________Method 2) A = b * h =
= (50 ½ in) * (23 <span>¼ in) =
= (</span>
in) * (
<span> in) ;
</span>
___________________________________________________________Note: "50 ½ " = [(50*2) + 1 ] / 2 =
;
Note: "23 ¼ " = [(23*4) + 1 ] / 4 =
;
____________________________________________________________
→ A = (
in) * (
in) ;
→ A =
in² =
in² ;
→ A = (9393/8) in² =
→
A = in² = 1174 ⅛ in² = 1174.125 in² .
________________________________________________________
Answer: 3/5
Step-by-step explanation: Using the place value chart, we can see that the decimal 0.6 is 6 tenths. So we can write 0.6 as the fraction 6/10.
Notice however that 6/10 is not in lowest terms.
So we need to divide the numerator and the denominator by the greatest common factor of 6 and 10 which is 2.
So if we divide the numerator and denominator by 2, we get 3/5.
So 0.6 can be written as the fraction 3/5 which is in lowest terms.
Image provided showing the place value chart.
Answer:
The answer is "It would decrease, but not necessarily by 8%".
Step-by-step explanation:
They know that width of the confidence level is proportional to a confidence level. As just a result, reducing the confidence level decreases the width of a normal distribution, but not with the amount of variance in the confidence level. As just a result, when a person teaches a 90% standard deviation rather than a 98 percent normal distribution, the width of the duration narrows.