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rewona [7]
4 years ago
13

Use the following compound interest formula to complete the problem. A = P (1 + StartFraction r over n EndFraction) superscript

n superscript t Currently you have two credit cards, H and I. Card H has a balance of $1,186.44 and an interest rate of 14.74%, compounded annually. Card I has a balance of $1,522.16 and an interest rate of 12.05%, compounded monthly. Assuming that you make no purchases and no payments with either card, after three years, which card’s balance will have increased by more, and how much greater will that increase be? a. Card I’s balance increased by $53.16 more than Card H’s balance. b. Card I’s balance increased by $13.45 more than Card H’s balance. c. Card H’s balance increased by $35.61 more than Card I’s balance. d. Card H’s balance increased by $49.06 more than Card I’s balance. Please select the best answer from the choices provided A B C D
Mathematics
1 answer:
Pavel [41]4 years ago
7 0

Answer:

A

Step-by-step explanation:

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3 years ago
Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (
IrinaVladis [17]

Answer:

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14  and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median  of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = \dfrac{9+9}{2}

median = \dfrac{18}{2}

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = \dfrac{12+13}{2}

Median = \dfrac{25}{2}

Median = 12.5

Low             Q1                Median              Q3                 High

6                  9                     11                      12.5                14

The interquartile range = Q3 - Q1

The interquartile range =  12.5 - 9

The interquartile range = 3.5

7 0
3 years ago
A surveyor standing at A notices two posts B and C on the opposite side of a canal. The posts are 120m apart. If the angle of si
AveGali [126]

Unfortunately there isn't enough information.

Check out the diagram below. We have segment BC equal to 120 meters long. Points B, C, D and E are all on the edge of the same circle. According to the inscribed angle theorem, angles BDC and BEC are congruent. This shows that the surveyor could be at points D or E, or the surveyor could be anywhere on the circle. There are infinitely many locations for the surveyor to be at, which leads to infinitely many possible widths of this canal.

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A farmer has a circular shaped field. Fertilizer
Aleonysh [2.5K]

Answer:

It will be $5 per square yard

Step-by-step explanation:

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Position vs time for two runners<br><br> Runner a and runner b
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Answer:

i8765

Step-by-step explanation:

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