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pychu [463]
3 years ago
11

What is another way to express 16

Mathematics
2 answers:
Akimi4 [234]3 years ago
8 0
128/8
16.0
6+10
8*2
123456789-123456773
Pavel [41]3 years ago
7 0
We can express 16 as
1) 4²
2) 2⁴

Hope this helps!
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How do I find number 2?
prisoha [69]

Answer:

  y = 3/4x +4

Step-by-step explanation:

From point A to point B, you show a rise of 3 units and a run of 4 units. (The rise is the difference in height of the first two squares; the run is the side length of the first square.) The ratio rise/run = 3/4 is the slope of the line you want.

The upper-left corner of the first square is the y-intercept of the line (4). So, in slope-intercept form, the equation of the dotted line is ...

  y = mx + b . . . . . m = slope; b = y-intercept

  y = 3/4x + 4

8 0
3 years ago
A number x increased by 17 is 106
Lorico [155]

Answer:

x = 89

Step-by-step explanation:

106 - 17 = 89

6 0
3 years ago
Solve a = D + C/B for d<br><br> d = ab - c<br> d = ab + c<br> d = a/b - c
harkovskaia [24]
Your answer is ab -c

multiply both sides by B
Then subtract C
6 0
3 years ago
How do you solve 4.23-5(0.04+0.09) step by step?
gtnhenbr [62]

Answer:

-0.04

Step-by-step explanation:

4.23-5= -0.77

-0.77*0.04= -0.03

-0.77*0.09= -0.07

-0.07 + -0.03= -0.04

8 0
3 years ago
The half life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am
Veronika [31]

Using an exponential function, it is found that:

a) N(t) = 75(0.5)^{\frac{t}{3.8}}

b) 37.5 grams of the gas remains after 3.8 days.

c) The amount remaining will be of 10 grams after approximately 11 days.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

A(t) = A(0)(1 - r)^t

In which:

  • A(0) is the initial value.
  • r is the decay rate, as a decimal.

Item a:

We start with 75 grams, and then work with a half-life of 3.8 days, hence the amount after t daus is given by:

N(t) = 75(0.5)^{\frac{t}{3.8}}

Item b:

This is N when t = 3.8, hence:

N(t) = 75(0.5)^{\frac{3.8}{3.8}} = 37.5

37.5 grams of the gas remains after 3.8 days.

Item c:

This is t for which N(t) = 10, hence:

N(t) = 75(0.5)^{\frac{t}{3.8}}

10 = 75(0.5)^{\frac{t}{3.8}}

(0.5)^{\frac{t}{3.8}} = \frac{10}{75}

\log{(0.5)^{\frac{t}{3.8}}} = \log{\frac{10}{75}}

\frac{t}{3.8}\log{0.5} = \log{\frac{10}{75}}

t = 3.8\frac{\log{\frac{10}{75}}}{\log{0.5}}

t \approx 11

The amount remaining will be of 10 grams after approximately 11 days.

More can be learned about exponential functions at brainly.com/question/25537936

4 0
2 years ago
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