2 answers:
Answer:
Given : A=(1,2)≡(x
1 ,y
1
) and B=(3,−2)≡(x
2
,y
2
)
Let M=(x,y) be the midpoint of AB
x=(
2
x
1
+x
2
) and y=(
2
y
1
+y
2
)
Then, x=
2
1+3
and y=
2
2−2
⟹x=2 and y=0
∴M=(2,0)
∴ Coordinates of the midpoint of AB is (2,0)
Explanation:
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