Answer:
y = 3
Step-by-step explanation:
y = k/x
xy = k
3 × 8 = k
k = 24
x = 8
y = 24/x
y = 24/8
y = 3
Answer:
4
Step-by-step explanation:
If you're rounding up:
(2.5 --> 3)
(3.3 --> 4)
<em>(Let me know if I'm misunderstanding something)</em>
Answer:
Step-by-step explanation:
Not entirely sure about the first one, but I'll try the others:
2- log base 8 (8x) = log base 8 (8) + log base 8 (x) = 1 + log base 8 (x)
3 - log base 3 (5^x) = x log base 3 (5)
4 - log base 2 (5/x) = log base 2 (5) - log base 2 (x) = In 5 - In x
5 - log base 2 (2^x) = x log base 2 (2) = x · 1 = x
To find how much older Leo is than John, we need to first assign our variables. In this case, let's say that x = Leo, y = Karla, and z = John. Now, let us turn words into numbers.
x = 2y
z = y - 7
Next, we need to create an equation for their combined ages. This is what the equation should look like:
x + y + z = 37
Now, just substitute the expressions we found for x and z. This is what we get:
2y + y + (y - 7) = 37
Solve for y:
2y + y + y - 7 = 37
4y - 7 = 37
4y = 44
y = 11
So now we have the value for y, which is Kayla's age. Therefore, just substitute the value for y back into the equations for x and z.
x = 2(y) => x = 2(11) => x = 22
z = y - 7 => z = 11 - 7 => z = 4
Now that we have the values for x, y, and z, all we need to do now is reassign them back to their respective names. Our final answer will be: John is 18 years older than Leo. The answer to your query would be E) 18. Hope this helps and have a nice day!