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Over [174]
3 years ago
9

Find the quotient. 2 1/3 ÷ 1 help

Mathematics
1 answer:
Jet001 [13]3 years ago
4 0

Answer:

2 \frac{1}{3}  \div 1 \frac{1}{3}  \\ = \frac{7}{3}  \div  \frac{4}{3}  \\ = \frac{7}{3}  \times  \frac{3}{4}  \\  =  \frac{7}{4}

<h3><u>PLEASE MARK ME BRAINLIEST</u></h3>
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If two dice are rolled one time, find the probability of getting: a sum grater than 10\
lilavasa [31]
If two dices are rolled once, you would have a total number of 6*6=36 possibilities.
To get a sum greater than 10:
A) one of your dices could be showing a 5, the other a 6. That’s two possibilities. Dice A being the 5 or dice B being the 5.
B) both of your dices could be showing 6s.
That’s one possibility.
So your overall possibility to get a sum greater than 10 is (1+2)/36 3/36=1/12
One twelfth.
4 0
3 years ago
The water level of a certain body of water is changing at a rate of W(t)=3/4cos(4-t/2) inches per hour, where t represents hours
Leni [432]

Answer:

The answer is below

Step-by-step explanation:

a) The integral \int\limits^{10}_{1 } {W(t)} \, dt means the total change in level of water in inches from 1 am to 10 am. That is the water level change measured in inches between 1 am and 10 am

b) 7 pm is represented as t = 19 hours, while midnight is represented as t = 24 hours, hence the water level change between 7 pm and midnight is:

\int\limits^{24}_{19 } {W(t)} \, dt\\\\

c) Using casio calculator to evaluate the integral gives:

\int\limits^{24}_{19 } {W(t)} \, dt\\\\ = 2.54 inches

D) The total daily change in water level = \int\limits^{24}_{0 } {W(t)} \, dt\\\\ = 0.35 inches

8 0
2 years ago
PLEASE HELP FAST! I will give brainlist!
Whitepunk [10]

Answer:

D or A

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the value of 6 in 70,681? Explain how you know.
Dafna11 [192]

Answer:

it's 100

Step-by-step explanation:

70000

0000

600

80

1

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6 0
2 years ago
The number of peanuts in bags is normally distributed with a mean of 172.5 peanuts and a standard deviation of 1.9 peanuts.
ValentinkaMS [17]
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