The 15th term in the given A.P. sequence is a₁₅ = 33.
According to the statement
we have given that the A.P. Series with the a = 5 and the d is 2.
And we have to find the 15th term of the sequence.
So, for this purpose we know that the
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.
And the formula is a
an = a + (n-1)d
After substitute the values in it the equation become
an = 5 + (15-1)2
a₁₅ = 5 + 28
Now the 15th term is a₁₅ = 33.
So, The 15th term in the given A.P. sequence is a₁₅ = 33.
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Answer:
i think its 8
Step-by-step explanation:
For this case we have that the relationship is direct.
Therefore, we have:

Where,
y: distance traveled in kilometers
x: number of liters of fuel
k: proportionality constant
We must look for the value of k. For this, we use the following data:
This car can travel 476 kilometers on 17 liters of fuel.
Substituting values we have:

From here, we clear the value of k:

Therefore, the relationship is:

For 1428 kilometers we have:

Clearing the amount of fuel we have:

Answer:
51 liters of fuel are required for the vehicle to travel 1,428 kilometers
Answer:
6
Step-by-step explanation:
3/4 / 1/8
3/4 x 8/1
24/4
6