Question

The area of the net the team uses is no more than 107.25 ft2. The width of the net is 3.25 feet.

Answer 1

Answer:

b

Step-by-step explanation:

Answer 2

Answer:

The inequality is $l\times (3.25)\leq 107.25$

Step-by-step explanation:

Given: Area of volleyball net= $107.25 ft^{2}$

          Width of Volleyball net= $3.25 \ ft$

Considering the volleyball net is in rectangular shape and l and w is length and width respectively.

Area of rectangle= $l\times w$

Now, using formula to form inequality

⇒ $l\times (3.25)\leq 107.25$

Next, using the inequality to find length of Volleyball net.

∴  $l\times (3.25)\leq 107.25$

Dividing both side by 3.25

⇒ $l= \frac{107.25}{3.25} = 33\ ft$

∴ l= 33 ft

The possible length of Volleyball net is 33 ft.