Answer:
there is no collision between the particles
Step-by-step explanation:
for the first particle
x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π
for the second particle
x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π
then for the collision
x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t
y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t = 2 cos t →(1/3) = 2
since 1/3 ≠ 2 there is no collision between the particles
Answer:
i think its D dont fullly take my word tho
Step-by-step explanation:
Answer:
4/10
Step-by-step explanation:
<em><u>Question:</u></em>
The equations in this system were added to solve for x. What is the value of x? -2x+y=8 5x-y=-5 3x=3
Options:
x = negative 3
x = negative 1
x = 1
x = 3
<em><u>Answer:</u></em>
The value of x is 1
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
-2x + y = 8 ------- eqn 1
5x - y = -5 ------- eqn 2
The above equations are added to solve for "x"
Add eqn 1 and eqn 2
-2x + y + 5x - y = 8 - 5
Combine the like terms
-2x + 5x + y - y = 3
Add the like terms
3x + 0 = 3
3x = 3
Divide both sides of equation by 3
x = 1
Thus the value of x is 1
