To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
I think you meant to type
4(n)-5=7.
4n = 7 + 5
4n = 12
n = 12/4
n = 3
Two equivalent fractions equations are
r + 6
6 + r <span />
This is how you do it :) let me know if you have any questions. Hope this helps :)
I’m thinking it would be c sorry if it’s incorrect .
