$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
y=\frac{1}{2}\\
x=2
\end{cases}\implies \cfrac{1}{2}=k2\implies \cfrac{1}{4}=k
\\\\\\
\boxed{y=\cfrac{1}{4}x}
\\\\\\
\textit{when x=3, what is \underline{y}?}\qquad y=\cfrac{1}{4}\cdot 3$

4 0

3 years ago

Kevin and Randy Muise have a jar containing 47 coins, all of which are either quarters or nickels. The total value of the coins

SVETLANKA909090 [29]

Ik but learn its simple but there is multiple answers

4 0

3 years ago

A population has a mean of 300 and a standard deviation of 40. Suppose a sample of size 100 is selected and is used to estimate

bazaltina [42]

Answer:

a: 0.9544 9 within 8 units)

b: 0.9940

Step-by-step explanation:

We have µ = 300 and σ = 40. The sample size, n = 100.

For the sample to be within 8 units of the population mean, we would have sample values of 292 and 308, so we want to find:

P(292 < x < 308).

We need to find the z-scores that correspond to these values using the given data. See attached photo 1 for the calculation of these scores.

We have P(292 < x < 308) = 0.9544

Next we want the probability of the sample mean to be within 11 units of the population mean, so we want the values from 289 to 311. We want to find

P(289 < x < 311)

We need to find the z-scores that correspond to these values. See photo 2 for the calculation of these scores.

We have P(289 < x < 311) = 0.9940

5 0

3 years ago