1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lapo4ka [179]
3 years ago
8

Rewrite the radical expression as an expression with rational exponents.

Mathematics
1 answer:
nadya68 [22]3 years ago
7 0

Answer: (\sqrt[3]{x} )^8

Step-by-step explanation:

Radical expression :

Cube root of any expression 'a' = \sqrt[3]{a}

Radical exponent:

'a' to the power n = a^n

Similarly cube root of x = \sqrt[3]{x}

cube root of x to the power of 8 = (\sqrt[3]{x} )^8

Now , the required radical expression with rational exponents for "cube root of x to the power of 8" = (\sqrt[3]{x} )^8

Hence, the required expression =(\sqrt[3]{x} )^8

You might be interested in
A bag contains marbles numbered 1 through 100. Zoe draws a marble. Then, without replacing the marble, she draws a second marble
Neporo4naja [7]
If starting out, there are 100 marbles and Zoe pulls out a 5 and doesn't replace it, then there are 99 marbles left to choose from. So, there are 9 digits 1-10 (not including #5) making the proportion you have left 9/99 which simplifies to 1/11
6 0
3 years ago
If a 24-kg mass stretches a spring 15 cm, what mass will stretch the spring 10 cm
natulia [17]

Answer:

<h2>16kg</h2>

Step-by-step explanation:

 This problem is borers on elasticity of materials.

according to Hooke's law,<em> "provided the elastic limit of an elastic material is not exceeded the the extension e is directly proportional to the applied force."</em>

F= ke

where F is the applied force in N

          k is the spring constant N/m

          e is the extension in meters

Given data

mass m= 24kg

extensnion=15cm in meters= \frac{15}{100}= 0.15m

we can solve for the spring constant k

we also know that the force F = mg

assuming g=9.81m/s^{2}

therefore

24*9.81=k*0.15\\235.44=k*0.15\\k=\frac{235.44}{0.15} \\k=1569.6N/m\\

We can use this value of k to solve for the mass that will cause an extension of  10cm= 0.1m

x*9.81=1569.6*0.1\\\\x= \frac{156.96}{9.81} \\\x= 16kg

5 0
3 years ago
Jimmy wants to serve iced tea at his birthday party. He purchases 14 containers filled with 1.5 liters of tea. Approximately how
jenyasd209 [6]

Answer:

5.5 gallons

Step-by-step explanation:

set up a proportion; Liters in numerator and Gallons in denominator

let x = approx number of gallons

<u> 21 </u> = <u> 3.8 </u>

x           1

3.8x = 21

x = 21 ÷ 3.8

x ≈ 5.5

4 0
3 years ago
Find the circumference to the nearest tenth
gregori [183]
C=3.14(15.6)
C=48.9-> 49 
4 0
3 years ago
What is the scale factor of the geometric sequence? <br> 200,100,50,25
Alchen [17]

The scale factor is 1/2 or .5 because 200*.5=100 and 100*.5=50 and so on

7 0
3 years ago
Other questions:
  • Describe the transformation of f(x)=x^3 to g (x)=-4 (x-1)^3+7
    11·1 answer
  • From a standard deck of playing cards, what is the probability of being dealt 5 diamonds?
    9·1 answer
  • A pond contains two kinds of fish, trout and bass, of which 20% are bass and 80% are trout. If you catch 5 fish at random from t
    10·2 answers
  • Solve the compound inequality and write the solution in interval notation: 34x−3≤3 or 25(x+10)≥0.
    14·1 answer
  • Help me guys pls pls pls i need a 70 or higher
    11·1 answer
  • Write a proportion that can be used to find the value of x. Do not solve.<br> x<br> 18<br> 32
    11·1 answer
  • Find the average rate of speed, expressed in miles per hour (unit rate). A post office truck delivered mail on a 9-mile route in
    13·1 answer
  • Can you help me please ​
    13·1 answer
  • Why did j ernest wilkins jr was the first to do something significant in math
    5·1 answer
  • Indicate the equation of the line, in standard form, that is the perpendicular bisector of the segment with endpoints (4, 1) and
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!