Answer:
We know that:
H(x) = |1 - x^3|
and:
We want to write H(x) as f( g(x) ) , such that for two functions:
So we want to find two functions f(x) and g(x) such that:
f( g(x) ) = |1 - x^3|
Where neither of these functions can be an identity function.
Let's define g(x) as:
g(x) = x^3 + 2
And f(x) as:
f(x) = | A - x|
Where A can be a real number, we need to find the value of A.
Then:
f(g(x)) = |A - g(x)|
and remember that g(x) = x^3 + 2
then:
f(g(x)) = |A - g(x)| = |A - x^3 - 2|
And this must be equal to:
|A - x^3 - 2| = |1 - x^3|
Then:
A = 3
The functions are then:
f(x) = | 3 - x|
g(x) = x^3 + 2
And H(x) = f( g(x) )
Hello!
∠GCE = 14° (corresponding angles)
∠GEC = 180° - 78° - 14° (sum of angles in a triangle)
∠GEC = 88°
4x + 88° = 180°
4x = 180° - 88°
4x = 92°
x = 23°
Absolute value of x minus 6 is less than y
one way is to jsut make all the x's positive, then subtract them from 6 and see if they are less
sorry for confusing, just read below
(-5,1)
1>|-5|-6
1>5-6
1>-1
true
(-1,-5)
-5>|-1|-6
-5>1-6
-5>-5
false
(5,-1)
-1>|5|-6
-1>-1
false
answer is (-5,1)
3 times negative 11 is negative 33 and 3 times 2 is 6, so you have negative 33 divided by 6 and that is negative 5.5
Answer:
-44.35
Step-by-step explanation:
1/4 = 0.25 (as 0.25 * 4 = 1)
-25 1/4 = -25.25
-25.25 - 19.1 = -44.35
