Answer:
183$
Step-by-step explanation:
.........................
Z-m=z+bx
z-m-z=z+bx-z
-m=bx
bx=-m
bx/b=-m/b; b=0
x=-m/b; b=0
Answer:
x=5.3
Step-by-step explanation:
.3(5x-1.5)=7.5
1.5x-.45=7.5
1.5x=7.95
x=5.3
Answer:
s = 22.5 m
Step-by-step explanation:
the equation for the speed change of a coach moving along a straight section of the road and starting braking at a speed of 20 m / s has the form v (t) = 25-5t. Using integral calculus, determine the coach's braking distance.
v (t) = 25 - 5 t
at t = 0 , v = 20 m/s
Let the distance is s.

Let at t = t, the v = 20
So,
20 = 25 - 5 t
t = 1 s
So, s = 25 x 1 - 2.5 x 1 = 22.5 m
The first one would be (-5,5) and the second one is (5,5) or 1.