All categories

2 years ago

Translate the following phrase into an algebraic expression: "4 more than the product of 3 and a number."

Mathematics

2 answers:

arsen [322]2 years ago

6 0

Answer:

4+3n

n can be any variable

Step-by-step explanation:

aliina [53]2 years ago

5 0

3(x) + 4
Hope this will help

You might be interested in

I need help with part b and c

Vikki [24]

I am not sure about b cut I think C is 10

5 0

3 years ago

In chemistry class 18 liters of 30% alcohol solution must be mixed with 20% solution to get 14% solution how many liters of 20%

alexdok [17]

If you are mixing a 30% solution with a 20% solution to obtain a 14% solution, you will never obtain a 14% solution.

5 0

3 years ago

Solve for the x variable

bagirrra123 [75]

Answer:

5x-5.2=7.3

5x=7.3+5.2

5x=12.5

x=12.5÷5

x=2.5

7 0

3 years ago

Read 2 more answers

Which of the following number lines shows the correct sum of the number above and 4?

zheka24 [161]

Answer:

Step-by-step explanation:

because on you have to add 4 to the number above. so 3+4 equals 7 so you move 4 spaces to the right on the number line to get you 7. so C is the correct answer

6 0

2 years ago

The general equation for a circle is a(x^2 + y^2) + bx + cy + d = 0. There is exactly one circle passing through the points (3,-

lidiya [134]

Answer:

The equation for this circle is 2c(x²+y²) - 8cx + cy = 0

Step-by-step explanation:

We can solve this problem replacing each of the points in the general equation and then solving the system of equations.

The fact that the circle passes by the point (3,-2) means that when x = 3, y = -2. So:

$a(3^{2} + (-2)^2) + 3b - 2c + d = 0$

$13a+ 3b - 2c + d = 0$

For (1, -2)

$a(1^{2} + (-2)^2) + b - 2c + d = 0$

$5a + b - 2c + d = 0$

For (0,0)

$a(0^{2} + (0)^2) + 0b - 0c + d = 0$

$d = 0$

Now we have to find a,b,c, from the following equations

13a+ 3b - 2c = 0

5a + b - 2c = 0

Since we have variables and 2 equations, i am going to write a and b as functions of c.

13a + 3b = 2c

5a + b = 2c

I will write b in the second equation as a function of a and c, and replace in the first equation

b = 2c - 5a

---------

13a + 3(2c-5a) = 2c

13a + 6cc -15a = 2c

-2a = -4c *(-1)

2a = 4c

a = 2c

-----------

b = 2c - 5a

b = 2c - 5(2c)

b = -8c

The solution for the system is (a,b,c) = (2c, -8c, c). So the equation for this circle is 2c(x²+y²) - 8cx + cy = 0

6 0

3 years ago