Answer:
The angle formed between CF and the plane ABCD is approximately 47.14°
Step-by-step explanation:
The given parameters are;
BC = 6.8
DE = 9.3
∠BAC = 52°
We note that the angles formed by the vertex of a cuboid are right triangles, therefore, by trigonometric ratios, we get;
sin∠BAC = BC/(The length of a line drawn from A to C)
∴ The length of the line drawn from A to C = BC/sin∠BAC
The length of the line drawn from A to C = 6.8/sin(52°) ≈ 8.63
∴ AC = 8.63
By trigonometry, we have;
The angle formed between CF and the plane ABCD = Angle ∠ACF


In a cuboid, FA = BG = CH = DE = 9.3


The angle formed between CF and the plane ABCD = Angle ∠ACF ≈ 47.14°
He means that 5.08 cm is a possible coordinate, and 50.8 mm is a possible coordinate
:)
4350? I'm not sure what you meant. All of those numbers are above 0.47. If you meant 0.750, 0.1950, 0.2150, or 0.4350, then it's 0.4350
An outlier, it's when a number is much greater or lower than all the rest of the numbers.