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lisabon 2012 [21]
3 years ago
15

Solve for x -4x-8 =-(5x+3)

Mathematics
2 answers:
devlian [24]3 years ago
7 0

Answer:

x=5

Step-by-step explanation:

-4x-8=-\left(5x+3\right)

<u>→ Expand:-</u>

<u />-\left(5x+3\right)

=-\left(5x\right)-\left(3\right)

<u>→ Apply minus rule:- </u>+\left(-a\right)=-a

=-5x-3

-4x-8=-5x-3

<u>→ Add 8 from both sides:-</u>

<u />-4x-8+8=-5x-3+8

-4x=-5x+5

<u>→ Add 5x from both sides:-</u>

<u />-4x+5x=-5x+5+5x

x=5

<u>OAmalOHopeO</u>

miskamm [114]3 years ago
5 0

Answer:

x = 5

Step-by-step explanation:

- 4x - 8 =  - (5x + 3) \\  - 4x - 8 =  - 5x - 3 \\  - 4x + 5x =  - 3 + 8 \\ x = -3 + 8\\ x = 5

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Answer: 35, 209, 171

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3 years ago
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Answer:

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2 years ago
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How much profit does the company make from producing and selling four soccer nets? $51 $80 $109 $137.
Oksanka [162]

The  profit does the company make from producing and selling four soccer nets is $109, the correct option is C.

<h3>What is profit?</h3>

Profit is a financial benefit that is realized when the amount of revenue gained from a business activity.

Given

|Soccer nets per day | Total Cost | Total Revenue |

| 1 | 7$ | $30 |

| 2 | 9$ | $60 |

| 3 | 10$ | $90 |

| 4 | 11$ | $120 |

| 5 | 13$ | $150 |

The total cost in the four soccer = $11

The total revenue in the four soccer = $120

The profit does the company make from producing and selling four soccer nets is;

\rm Profit = Total \ revenue -Total \ cost\\\\Profit= 120-11\\\\Profit = 109

Hence, the  profit does the company make from producing and selling four soccer nets is $109.

To know more about profit click the link given below.

brainly.com/question/6402318

4 0
2 years ago
Look at this please i dont need help im just trying to tell everybody something
Alja [10]

Answer:

yasssasasasas

Step-by-step explanation:

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3 years ago
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A bag of colored candles contains 18 red candles and 27 blue candles. What percent of the candles are red?
Bond [772]
A whole bag of colored candles has 45 candles in it.
If 18 are red, then 27 are blue.
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* If you need anymore help or have any questions, feel free to ask me! I'd be happy to help you!

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