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katovenus [111]
3 years ago
11

Enrique and Yolanda collected 500 pieces of candy on Halloween. they gave half of their candy to charity. Yolanda took 180 piece

s of the candy and Enrique took the rest . Enrique told his mother he got 64% of the candy what did Enrique do wrong in calculating his parentage.
Mathematics
1 answer:
Ivenika [448]3 years ago
4 0

500 − 250  = 250 pieces left after donation

Yolanda got  180 pieces....then Enrique  got 70 pieces

So he got   70 /250  = 7/25  =  28%  of the remaining candy

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Assume that females have pulse rates that are normally distributed with a mean of u = 75.0 beats per minute and a standard devia
Elan Coil [88]

Answer:

36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 75, \sigma = 12.5

Find the probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

This is the pvalue of Z when X = 81 subtracted by the pvalue of Z when X = 69.

X = 81

Z = \frac{X - \mu}{\sigma}

Z = \frac{81 - 75}{12.5}

Z = 0.48

Z = 0.48 has a pvalue of 0.6844

X = 69

Z = \frac{X - \mu}{\sigma}

Z = \frac{69 - 75}{12.5}

Z = -0.48

Z = -0.48 has a pvalue of 0.3156

0.6844 - 0.3156 = 0.3688

36.88% probability that her pulse rate is between 69 beats per minute and 81 beats per minute.

3 0
3 years ago
Read 2 more answers
How do I solve these 2 problems? What’s the answer
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1. substitution

2. transitive property

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