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3 years ago

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Mitchell bought 76 lb of cocoa powder for her Bakery every day she use the same amount of cocoa powder to make Bakery items afte

r 10 days Mitchell was left with 20.2 pounds of cocoa powder on average how many pounds of cocoa powder did Mitchell use each day

1 answer:

Shkiper50 [21]3 years ago

3 0

In days she used 55.8 pounds in total
so your answer is 55.8

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Write an equation in general form for the line passing through (-12,-1) and perpendicular to the line whose equation is 6x-y-4=0

Rus_ich [418]

The Solution:

Given the equation of a line:

$6x-y-4=0$

We are required to find the equation of a line that is perpendicular to the given line and passes through the point (-12,-1).

Step 1:

Determine the slope of 6x-y-4=0.

$\begin{gathered} \text{ Express y in terms of x.} \\ 6x-4=y \\ y=6x-4 \end{gathered}$

The coefficient x, after making y the subject of the formula, is the slope of the given line. That is:

$\begin{gathered} \text{ The slope of }6x-y-4=0\text{ is 6} \\ \\ Slope=m_1=6 \end{gathered}$

Step 2:

Find the slope of the required line:

Since the two lines are perpendicular, the slope is:

$\begin{gathered} m_2=\frac{-1}{m_1}=\frac{-1}{6} \\ \end{gathered}$

Step 3:

Find the equation of the line that passes through point (-12,-1)

By formula,

$y-y_1=m_2(x-x_1)$

In this case,

$\begin{gathered} x_1=-12 \\ y_1=-1 \end{gathered}$

Substituting these values in the formula, we get the required equation is:

$\begin{gathered} y--1=\frac{-1}{6}(x--12) \\ \\ y+1=-\frac{1}{6}(x+12) \end{gathered}$

Cross multiplying, we get

$\begin{gathered} 6y+6=-x-12 \\ \\ 6y+x+6+12=0 \\ \\ 6y+x+18=0 \end{gathered}$

Therefore, the correct answer is:

$6y+x+18=0$

5 0

1 year ago

Anyone know this??????

Ksju [112]

Answer:

Verticle or straight line.

Step-by-step explanation:

I learned that in elementary.

4 0

3 years ago

Plz help in solving these 2 questions with steps and explanation!!

fomenos

Answer:

$\large\boxed{Q1:\ x=2\ or\ x=5}\\\boxed{Q2:\ x=1-\sqrt{21}\ or\ x=1+\sqrt{21}}$

Step-by-step explanation:

$\text{Use the quadratic formula:}\\\\ax^2+bx+c=0\\\\\text{If}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\==========================================$

$\bold{Q1}\\\\x^2-7x+10=0\\\\a=1,\ b=-7,\ c=10\\\\b^2-4ac=(-7)^2-4(1)(10)=49-40=9>0\\\\\sqrt{b^2-4ac}=\sqrt9=3\\\\x_1=\dfrac{-(-7)-3}{2(1)}=\dfrac{7-3}{2}=\dfrac{4}{2}=2\\\\x_2=\dfrac{-(-7)+3}{2(1)}=\dfrac{7+3}{2}=\dfrac{10}{2}=5\\\\========================================$

$\bold{Q2}\\x^2-2x=20\qquad\text{subtract 20 from both sides}\\\\x^2-2x-20=0\\\\a=1,\ b=-2,\ c=-20\\\\b^2-4ac=(-2)^2-4(1)(-20)=4+80=84>0\\\\\sqrt{b^2-4ac}=\sqrt{84}=\sqrt{4\cdot21}=\sqrt4\cdot\sqrt{21}=2\sqrt{21}\\\\x_1=\dfrac{-(-2)-2\sqrt{21}}{2(1)}=\dfrac{2-2\sqrt{21}}{2}=1-\sqrt{21}\\\\x_2=\dfrac{-(-2)+2\sqrt{21}}{2(1)}=\dfrac{2+2\sqrt{21}}{2}=1+\sqrt{21}$

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3 years ago

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The price of A cup of coffee was $2.20 yesterday today the price rose to $2.55 find the percentage increase round your answer to

Anna11 [10]

.35 is the raise of the cup of coffee

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3 years ago

Omar has $32 to spend at the store. He bought one bag of apples which cost $4 each, 3 mangoes which cost $2 each, one block of c

-Dominant- [34]

Moolah to spend: $32.00

Apples: $4.00

Mangoes x 3: $6.00

Cheese (<em>really </em>expensive cheese): $5.00

Pizza: $15.00

$32.00 -$32.00 - $30.00 = change Omar received ($4.00+$6.00+$5.00+$15.00) = change Omar received

$32.00 - $30.00 = change Omar received

$2.00 = change Omar received (assuming everything he brought was tax free -- if it was, then that made up for the outrageous price for that block of cheese)

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3 years ago

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