Answer: 2 x - 3 y = 6 i think but let let me know if i'm wrong
Answer:
The 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population proportion <em>P</em> is:

The information provided is:
<em>x</em> = number of students who responded as"yes" = 70
<em>n</em> = sample size = 200
Confidence level = 95%
The formula to compute the sample proportion is:

The R codes for the construction of the 95% confidence interval is:
> x=70
> n=200
> p=x/n
> p
[1] 0.35
> s=sqrt((p*(1-p))/n)
> s
[1] 0.03372684
> E=qnorm(0.975)*s
> lower=p-E
> upper=p+E
> lower
[1] 0.2838966
> upper
[1] 0.4161034
Thus, the 95% confidence interval for the true proportion of university students who use laptop in class to take notes is (0.2839, 0.4161).
Answer:
The slope is negative. The relationship is proportional
Step-by-step explanation:
Answer:
C) 1/5
Step-by-step explanation:
Answer:
The Pacific seahorse eats 8 shrimp per day
Step-by-step explanation:
<u><em>The complete question is</em></u>
As a part of its diet, a Pacific seahorse eats about 56 shrimp per week. It eats the same amount each day.
a) How much shrimp does the Pacific seahorse eat per day?
Complete the statement with the unit rate.
The Pacific seahorse eats _____ shrimp per day.
Part a) How much shrimp does the Pacific seahorse eat per day?
Let
x ---> the number of shrimp that the Pacific seahorse eats per day
we know that
The number of shrimp that the Pacific seahorse eats per day, multiplied by the number of days in a week, must be equal to 56 shrimp

so
The linear equation that represent this situation is equal to

solve for x
Divide by 7 both sides

therefore
The Pacific seahorse eats 8 shrimp per day